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Bash string replace

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# 1  
Old 11-15-2009
Bash string replace
Bash shell. I'm trying to filter a string taken from user input. I can replace one word at a time. This method supports regex, so is it possible to replace various words at a time?
Code:
STRING="Hello World! word1 word2";

FILTERED=${STRING/word1|word2/}; # Not working: replace 2 or more words ???

echo $FILTERED;

# 2  
Old 11-15-2009
Parameter expansion uses shell pattern matching, not regex.
You could use e.g. to filter out either or both words and the space before it.
Code:
FILTERED=${STRING//@( word1| word2)/}

You need to use a double slash otherwise it will just match one word in case there are two matching words.

or, if you do not seek to filter out these specific words, just plain:
Code:
FILTERED=${STRING% * *}

Last edited by Scrutinizer; 11-15-2009 at 03:02 PM..
# 3  
Old 11-15-2009
I tried this code but is not functional (at least in bash). FILTERED still outputs the string unchanged. The second code posted does work though.


FILTERED=${STRING//@( word1| word2)/}
# 4  
Old 11-15-2009
Does this work?

bash code:
Code:
shopt -s extglob
STRING="Hello World! word1 word2"
FILTERED=${STRING//@( word1| word2)/}
echo $FILTERED



---------- Post updated at 12:55 PM ---------- Previous update was at 12:28 PM ----------

This should work too:
Code:
FILTERED=${STRING/+( word1| word2)}

# 5  
Old 11-15-2009
Yes, shopt was missing. Smilie
# 6  
Old 11-22-2009
Quote:
Originally Posted by Scrutinizer


This should work too:
Code:
FILTERED=${STRING/+( word1| word2)}

Bonjour,

Comment se nomme ce type de filtre ? es-ce les expressions régulières ?
# 7  
Old 11-22-2009
It is called extended shell pattern matching, also called extended globbing. These are not regular expressions.
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