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Shell Programming and Scripting

List the files with string

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# 1  
Old 11-13-2009
List the files with string
I want to list all the files which are having today's date in its header...

Please let me know if this can be achveived by a single command
# 2  
Old 11-13-2009
Code:
grep $(date) *

# 3  
Old 11-13-2009
Code:
printf "'%s'" $(date "+%m/%m/%Y") | read dt && grep -l $dt /directory/to/search/*

# 4  
Old 11-14-2009
MySQL
Hi Steady and Jim,

I want to search Today's date only in the file header .. I dont want to search through the file content.

The search will be performed on the all files in the directory and to get the filenames which is having the Today's date on its header,

Please let me know if I am not clear.

Please help me if this can be achieved in a command.

Thank you,
# 5  
Old 11-14-2009
then you should provide your sample input file
# 6  
Old 11-14-2009
MySQL my workbook code
Hi,
My sample file will be like

H|ABC|DEF|20091112
D|abc|adsf|asdf|asdf
D|abc|adsf|asdf|asdf
D|abc|adsf|asdf|asdf
D|abc|adsf|asdf|asdf
T||abc|adsf|asdf|asdf

I am novice to shell scripting. but i tried to prepare a script like below.

Code:
EtlDate='20091112';
INBOUNDDIR='/cba_app/BANKWEST/BW117/DEV/inbound'
for fname in $INBOUNDDIR/abcb_akf840*.csv; do
head -1 $fname | grep $EtlDate > NULL
if(( $? == 0 )); then
    echo $fname
  fi

done


I want a command to list out the filenames with the date in the file header...
# 7  
Old 11-14-2009
gawk
Code:
$ EtlDate='20091112'
$ awk -v d="$EtlDate"  -F"|" 'FNR==1&& $NF==d{print "found "d" in "FILENAME;nextfile}' file*
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