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Insert external variable in a AWK pattern

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# 8  
Old 11-13-2009
Quote:
Originally Posted by antuan
i tested all cases.
note that $id is an external variable, and its what i want to put as AWK pattern.. Should I use the -v option ? Please complete my command, so I will understand you better. thanks

See my further comments in the previous post.

---------- Post updated at 11:37 AM ---------- Previous update was at 11:32 AM ----------

It seems you're using GNU AWK (you're using multi-character RS).
So, if the external variable is exported you can use something like this:

Code:
$0 ~ ENVIRON["id"]

In this last case you don't need to use pre (-v) or post (var= ...) assignment.
# 9  
Old 11-17-2009
Thank you for your help radoulov,


In the end I got the brute force solution, redirecting the command to an aux script file pasting the external variable into the awk command and executing the file. It is not the most elegant solution, but it's working properly.Smilie
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