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Getting multiple messy lines into one single line

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# 8  
Old 11-13-2009
And another one:

Code:
awk 'NF { sub(/ $/, x); r = r ? r FS $0 : $0 }
/:END:/ { print r; r = x }' infile

# 9  
Old 11-14-2009
Quote:
Originally Posted by radoulov
And another one:

Code:
awk 'NF { sub(/ $/, x); r = r ? r FS $0 : $0 }
/:END:/ { print r; r = x }' infile

Hi Radoulov

I don't get what you are doing with the sub function, from reading up on sub it looks like you are changing any space on the end of a line to an x from what I can see. How does this work?Smilie
# 10  
Old 11-14-2009
I think it is the same as:
Code:
awk 'NF { sub(/ $/, ""); r = r ? r FS $0 : $0 }
/:END:/ { print r; r = "" }' infile

, but x (being unitialized) contains "" and is therefore equivalent but only one character instead of two so it shortens the expression.
# 11  
Old 11-14-2009
Quote:
Originally Posted by Scrutinizer
I think it is the same as:
Code:
awk 'NF { sub(/ $/, ""); r = r ? r FS $0 : $0 }
/:END:/ { print r; r = "" }' infile

, but x (being unitialized) contains "" and is therefore equivalent but only one character instead of two so it shortens the expression.
Exactly.
Just to avoid doubling the space after substituting the newline with FS.
# 12  
Old 11-14-2009
Code:
awk 'BEGIN{RS="";FS="\n"}{$1=$1;print}'

If you don't like the extra spaces due to the trailing spaces at the end of the line from the input, do
Code:
awk 'BEGIN{RS="";FS=" *\n"}{$1=$1;print}'

# 13  
Old 11-14-2009
So it could be shortened to:
Code:
awk 'BEGIN{RS="";FS=" *\n"}$1=$1'

Nice, but this is relying on the presence of empty lines between records. If that is always the case fine, but the OP wasn't specific about that IMO.
# 14  
Old 11-14-2009
Quote:
Nice, but this is relying on the presence of empty lines between records[...]
... and it will fail if there are one or more empty lines inside the logical record (between ^:@ and :END:).
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