How to convert "Nov 9 11:35:28 2009" to "200911091135"


 
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# 1  
Old 11-09-2009
How to convert "Nov 9 11:35:28 2009" to "200911091135"

Using AIX 5.3 and /user/bin/ksh.

Anyone have a quick way to convert the string date

Nov 9 11:35:28 2009 to 200911091135

I know I could create a table of months and find the month number by searching the list, but I was hoping there was some handy little known command to do this type of date conversion to save me the trouble.

Thanks,
Troy

Last edited by troym72; 11-09-2009 at 02:29 PM..
# 2  
Old 11-09-2009
Code:
$
$ date -d "Nov 9 11:35:28 2009" +%Y%m%d%H%M
200911091135
$
$ date -d "Apr 1 9:5:7 2009" +%Y%m%d%H%M
200904010905
$

tyler_durden
# 3  
Old 11-09-2009
Smilie

Code:
/>date -d "Nov 9 11:35:28 2009" +%Y%m%d%H%M
date: illegal option -- d
Usage: date [-u] [+Field Descriptors]

Smilie

Last edited by troym72; 11-09-2009 at 02:30 PM..
# 4  
Old 11-09-2009
what about man date ?
# 5  
Old 11-09-2009
I have the same problem...

date -d ###### date: illegal option -- d

I'm on bash....on snow leopard

man date give this.

Code:
     -d dst  Set the kernel's value for daylight saving time.  If dst is non-
             zero, future calls to gettimeofday(2) will return a non-zero for
             tz_dsttime.

# 6  
Old 11-09-2009
Can't help with my version of GNU date Smilie
Code:
       -d, --date=STRING
              display time described by STRING, not ‘now'

# 7  
Old 11-09-2009
Well if you have Perl, then:

Code:
$
$ d="Nov 9 11:35:28 2009"
$
$ echo $d | perl -MDate::Parse -ne '@x=split; @y=strptime("$x[1] $x[0] $x[3] $x[2]");
                                    printf("%d%02d%02d%02d%02d\n",(1900+$y[5]),($y[4]+1),$y[3],$y[2],$y[1])'
200911091135
$
$ d="Apr 1 9:5:7 2009"
$
$ echo $d | perl -MDate::Parse -ne '@x=split; @y=strptime("$x[1] $x[0] $x[3] $x[2]");
                                    printf("%d%02d%02d%02d%02d\n",(1900+$y[5]),($y[4]+1),$y[3],$y[2],$y[1])'
200904010905
$
$

tyler_durden
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