Shell Programming and Scripting

Hi All

Can u help me..
My problem is comment (#) a line where a word exists in that line

sample:

cat /tmp/file.txt

monitor 192.168.1.11 Copying files in current directory 1
monitor 192.168.1.1 Copying files in current directory 2
monitor 192.168.1.12 Copying files in current directory 3
monitor 192.168.1.14 Copying files in current directory 4
monitor 192.168.1.15 Copying files in current directory 5
monitor 192.168.1.12 Copying files in current directory 6
monitor 192.168.1.166 Copying files in current directory 7
monitor 192.168.1.12 Copying files in current directory 8
monitor 192.168.1.112 Copying files in current directory 9

so what is command to comment (#) the lines where the word "192.168.1.12" exists in file /tmp/file.txt

Thx.
Darren

Code:

# awk '/192.168.1.12/ { $0="#"$0 } 1' /tmp.file.txt
monitor 192.168.1.11 Copying files in current directory 1
monitor 192.168.1.1 Copying files in current directory 2
#monitor 192.168.1.12 Copying files in current directory 3
monitor 192.168.1.14 Copying files in current directory 4
monitor 192.168.1.15 Copying files in current directory 5
#monitor 192.168.1.12 Copying files in current directory 6
monitor 192.168.1.166 Copying files in current directory 7
#monitor 192.168.1.12 Copying files in current directory 8
monitor 192.168.1.112 Copying files in current directory 9

or
sed -i "s/.*192.168.1.12.*/#&/" /tmp/file.txt

Thank You. The sed example did exactly what I wanted.