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Shell Programming and Scripting

Finding relative position in a file

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# 1  
Old 10-27-2009
Finding relative position in a file
Hi,

I have a file like

123
aaaaaaaaa
ddddddddd
vvvvvvvvv
345
ssssssssssss
dddddddddd
fffffffffff
dddd
ff
567
---------
sssssssss
ddddddd
eeeeeeeee

I want to find the position of all the numeric fields in this files? how can we do this?
# 2  
Old 10-27-2009
Going with your example file:
Code:
$ cat /tmp/test.txt
123
aaaaaaaaa
ddddddddd
vvvvvvvvv
345
ssssssssssss
dddddddddd
fffffffffff
dddd
ff
567
---------
sssssssss
ddddddd
eeeeeeeee
$ grep -n '[0-9]' /tmp/test.txt | cut -d: -f1
1
5
11

# 3  
Old 10-27-2009
Thanks a ton Pludi..
# 4  
Old 10-27-2009
Look if your grep supports the -n flag:
Code:
$ cat myfile.txt
123
aaaaaaaaa
ddddddddd
vvvvvvvvv
345
ssssssssssss
dddddddddd
fffffffffff
dddd
ff
567
---------
sssssssss
ddddddd
eeeeeeeee

$ grep -n "[0-9]" myfile.txt
1:123
5:345
11:567

# 5  
Old 10-27-2009
Another way:

Code:
awk '/[0-9]/{print NR}' file

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