Shell Programming and Scripting

Hello All,

I want to delete the files based on the days. like, Files available under directory /abc want to delete if they are older than 15 days.
Files available under directory /pqr want to delete if they are 7 days old and some files under directory /xyz should get deleted if they are older than 3 days. The Script will be executed through Cronjob at particular Time on daily basis.
While deleting the files it should not check for Sat and Sunday.

Like, if the script executed today, while deleting the files under directory /xyz (older than 3 days) should not delete the files with date of Monday, Friday and Thursday.
The date format on the files will be yyyymmdd.

Thank you very much in advance.

And where is your issue?

You are not expecting us to write the code for you without having at least tried something, are you?

I didn't asked to write the code for me. I just asked how to avoid the Saturday and Sunday while calculating the days.
I have written day's functions like.

function back_3days
{
typeset today=$(date +%Y%m%d)

LASTDAY=$(prev_day $today)
LASTDAY=$(prev_day $LASTDAY)
LASTDAY=$(prev_day $LASTDAY)
print $LASTDAY
}

where prev_day will calculate the total date's in a month and provide the date of the prev_day.

What about weekends then, will cron job run?
In which case it will erase on sunday the file it should not on monday...

The files will be generated only from Monday to Friday. No file will generate on weekends. Cronjob will run only on these 5 days.

So your cron on friday should count on 3 days, and the other week days on 5 (thursday shall not touch monday files and wednesday, you have the weekend...)