How can i apply crono or cronotab to my data? I think periods of 1 hour are the best to analze, dont you agree?
I should count the number of ips per hour......so the count i have already made :
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Cron and cronotab schedule a job to be done according to the local time. But my case is different, so, based on the data i have - log file - how can i collect the date/time and split them into chunks of 1 hour....of course each time is associated to a ip address. Any ideias?
Yes, that is exactly what i want. In the specific hour a chunk of information, the time, date and its mapping to the ip address. Should the files be split into seperate files having for example the title (month, day, hour), i am not sure of the best solution.
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Maybe a Array of Hashes could be the best solution ?
Thanks! I changed the pattern to a time range like and got a strange output :
The counting is done, but part of the ip vanished!
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ok, sorry, i have it working, my file had more than one space between each scalar...
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Hi again,
Is it possible to put this in a perl script or a shell unix script? This is powerfull, but it only works changing the ranges each time. Automation of the process would indeed optimize work! Having a file that could be run from the console, and according to its granularity, split the file and data into severel intervals and sub-files of 1 hour, or split the file and data into subfiles of days, or if bigger splitting into weeks. I look foward from hearing your advice...
So far, you can just take this line and put it in a file called dosomething.sh for example, change it's permissions with chown +x dosomething.sh and fire it off with ./dosomething.sh.
Sure, this can be done in perl too. But that's a job for someone else
So I'm stumped.
First... APOLOGIES... my work is offline in an office that has zero internet connectivity, as required by our client. If need be, I could print out my script attempts and retype them here. But on the off chance... here goes.
I have a text file (file_source) of terms, each line... (3 Replies)
Hi All,
I have a log file where every line contains a date and some other data, i want to grep only the date from every line to a different file.
Please help how to get this.
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I have a log file and I have two unique strings which represent the start and end of the text I want to obtain.
How can I get all the text inbetween this start string and the end string?
Thanks (2 Replies)
Guys ..
Need to pull this highlighted strings irrespective of line numbers & should be echoed . But these strings are from Outfile from different dir. In which way this can be grepped ?? Need an idea
http-timeout 120 seconds
persistent-timeout 180 seconds
host-rewriting on
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I need to know if anyone can assist me on how to grab the last (we'll just say "x" minutes) of a log file. How do you tell the grep command without specifying an exact window of time? (So relative instead of absolute.)
Thanks,
Jon (2 Replies)
Hey All,
I have to grep for an error from a file and get the results of errror in a different file......
But there should be no duplicate entries. Can anyone help me in giving a shell script for this
This is file which contains pattern error which I am supposed to grep and put this in a... (4 Replies)
I wrote this script for:
1. Get the Web log for today
2. Give me a list of all the IP addresses that have accessed the web server today
3. Remove a list of known IPs listed in a file (line by line)
4. Mail the final file to selected recipients.
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Hi
I was wondering if it's possible to use a command to get the first 3 characters of a line in a text file, I tried grep but it returns the whole line but I am only interested in the first 3 characters. Is this possible with grep or I need any other command?
Also is it possible deleting from... (2 Replies)