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bash scripting: using multiple 'for loops'??

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# 1  
Old 10-14-2009
bash scripting: using multiple 'for loops'??
Hey guys,

I'm kinda a noob at scripting. I am trying to create a script that uses multiple for loops with the lsiutility to monitor disk health on a system.
The script runs, but it will continually echo an infinite number of LogVolumes when there are only 2 per virtual disk on my server. It's probably something simple. Any sugguestions?

Code:
#!/bin/bash
IFS=$'\x0A'
num_virt_disk=`/usr/bin/lsiutil -p -a 0|grep 'MPT Port found'|awk '{print $1}'

for ((i=1; i<=$num_virt_disk; i++))
do
	num_log_vol=`/usr/bin/lsiutil -p${i} -a 1,21,1,0,0,0|grep volume|awk '{print $1}'`

for ((x=0; i<=$num_log_vol; x++))
	state=`/usr/bin/lsiutil -p${i} -a 1,21,3,0,3,1,0,0,0|grep State|awk '{print $3}'|sed 's/,//g'`

        if [ "$state" = "optimal" ]
        then
                echo -e "OS|Linux|Disks|VirtualDisk${i}|LogVolume${x}|Status\t0\t0\t"
        else
                echo -e "OS|Linux|Disks|VirtualDisk${i}|LogVolume${x}|Status\t1\t2\t"
        fi
done
done

Last edited by jim mcnamara; 10-14-2009 at 05:56 PM.. Reason: code tags, please...
# 2  
Old 10-14-2009
Hi.

The problem might be here:

Code:
for ((x=0; i<=$num_log_vol; x++))

# 3  
Old 10-14-2009
AH!
Thank you very much! I totally didn't catch that one!
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