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How to read n number of lines from a file

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Top Forums Shell Programming and Scripting How to read n number of lines from a file
# 36  
Old 11-12-2009
Quote:
Originally Posted by varsha
hello.....

In result the averages are not in order so instead of gawk i used /usr/xpg4/bin/awk but it throws me error showing No such file or directory



Help meSmilieSmilieSmilieSmilie





ThanksSmilieSmilieSmilie


if you don't have /usr/xpg4/bin/awk modify my code to the below and use gawk

Code:
gawk '{for (i=1;i<=NF;i++){a[i]+=$i;b[i]++ ; if(nf <= NF) {nf=NF}  } }

END{printf "Avrg  " ; for (i=1;i<=nf;i++) {printf "%s %s",a[i]/b[i],( i <= nf ) ? " " : "\n" } print "" }
'   file.txt

SmilieSmilieSmilie
Last edited by ahmad.diab; 11-12-2009 at 04:53 PM..
# 37  
Old 11-25-2009
Help!!
hello everybody,


I have problem in my script , it is for finding avg in column wise it is working fine wen all the columns have equal no of rows but it is not working when there disordered no of rows in columns

for eg :

Code:
3 4 5 7  8                                            
4 7 2 5                                                
5 6 8     6                                              
6 7                                                       
-------------                                          
Avg:4.5 6


but my ans should be like this given below:

Code:
3 4 5 7 8
4 7 2 5
5 6 8   6
6 7
---------------
Avg:4.5 6 5 6 7


my script is given below:

Code:
#!/bin/bash
echo "enter file name"
read file
cat $file
awk 'BEGIN {FS=OFS=" "} { for (i=1; i<=NF; i++) sum[i] += $i; j=NF }
END { printf "%s%s", "------------------", "\nAvg"; for (i=1; i <= j; i++) printf "%s%s", OFS, sum[i]/NR; printf "\n"; }' $file


I belive my qn have mentione clearly. plz anybody help meSmilieSmilieSmilieSmilie


Thanks in advanceSmilieSmilieSmilie
Last edited by Franklin52; 02-16-2010 at 07:05 AM.. Reason: Please use code tags!
# 38  
Old 12-09-2009
Reply Plzzzzzzzz
Till today there is no help foe meSmilieSmilieSmilie




Anyone help me plzSmilieSmilieSmilie



ThanksSmilieSmilieSmilie
# 39  
Old 12-09-2009
Code:
gawk '{for (i=1;i<=NF;i++){a[i]+=$i;b[i]++ ; if(nf <= NF) {nf=NF}  } }

END{printf "Avrg  " ; for (i=1;i<=nf;i++) {printf "%s %s",a[i]/b[i],( i <= nf ) ? " " : "\n" }
 print "" }
'   file.txt

# 40  
Old 12-10-2009
Thanks
Heyyyyyyy it workedSmilieSmilie





Thanks a lot friendSmilieSmilie
# 41  
Old 02-16-2010
Hello frds!!!
I again need your help


I have a file let us name x which contains as follows
Code:
1    3     4    5   7
6    2     1    6   0 
2    4     9    7   1
0    4     5    7   0
6    0     7    0   0

In this above data i want to find max num for 2nd column after finding that it should print its respective row and my output should b displayed as another file.I can have so many columns and rows its for eg i 600 rows and 15 columns

I want my output as like below

Code:
max=4
respective rows=2    4     9    7   1


I think i have explained my question of my knowldge


waiting for ur help frdsSmilieSmilie


Thanks in advanceSmilieSmilieSmilie
Last edited by Franklin52; 02-16-2010 at 06:49 AM.. Reason: Please use code tags!
# 42  
Old 02-16-2010
Something like this:

Code:
 
awk -v max=0 'max < $2 { max=$2 ;row=$0 ;next } END { print "max=" max "\n" row }' input_file
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