Shell Programming and Scripting

Hey everyone
Can anyone please write me a script to display numbers in descending order dynamically i.e if the user enter a number say 100 then the output should be like 100 99 ....so on till 0
I tried using the logic as for ((i =1; i<=100; i--) but the it goes into a infinite loop since even the negative numbers are less than any given postive number entered by a user

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This isn't a homework problem iam new to Linux and shell scripting altogether and besides iam new to programming too i recently joined as an intern in QA department of voip company.If this still isnt the proper section to post it,Iam sorry and i will see that i wont repeat such mistakes in the near future
sorry again

Code:

for ((i=100;i>=0;i--));do echo $i;done

http://abs.traduc.org/abs-5.0-fr/ch10.html

Using "standard" linux "tools"

Code:

echo "Enter a number: "
read NUMBER
seq 0 ${NUMBER:-100} | tac

seq is not standard, though it is common; tac is not standard and is less common than seq.

But you don't need tac if you are using seq:

Code:

seq NUMBER -1 0

The standard way is:

Code:

read n
while [ $n -ge 0 ]
do
  printf "%d\n" "$n"
  n=$(( $n - 1 ))
done

In bash:

Code:

eval "printf '%d\n' {$NUMBER..0}"

I'm finding it increasingly difficult as I move from "proper UNIX" to linux to know what is standard.

There are just so many distributions of Linux about that all bets are off as to what versions of what anyone might have.

On AIX for example, "grep -p" is great for extracting stanzas (paragraphs) from files. But that's not standard I guess as GNU grep doesn't have it.

Add to that finds maxdepth, sed's in-place replacement... etc., etc.

Live and learn.

---
forgot to mention the worst one, echo -n (or echo minus anything)