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how to validate a field when it is blank using awk prog

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Top Forums Shell Programming and Scripting how to validate a field when it is blank using awk prog
# 1  
Old 09-19-2009
how to validate a field when it is blank using awk prog
Hi,

I tried the below piece of code for my script to check whether it has a blank space for a particular field.

Code:
 
if(f10==/[[:blank:]]/){
print "Field 10 is Correct";}
else{
print "Field 10 is Wrong"; }

Quote:
But when field10 holds a value
Output should be :" Field10 is Wrong"
but the Actual Output : "Field10 is correct"
Please help me to know whether the "if" condition applied here is correct or do i need to specify it differently for checking blank space.

Thanks In Advance
Meva.
# 2  
Old 09-19-2009
Assuming the field separator is comma...
Code:
 
awk -F"," '{if($10==""){
  print "Field 10 is Correct";}
  else{
  print "Field 10 is Wrong"; }}' infile

# 3  
Old 09-19-2009
Actually the column values are stored in a variable like f1,f2....f10... and so on...

So now how do i check for the blank space stored in this variable?

I tried the below specified piece of code for a particular field

Code:
if(f10==""){
print "Field 10 is Correct";}
else{
print "Field 10 is Wrong"; }

but it dint work? it gave me the wrong results for my validation....is that i have used it wrongly or is there any other option?

Please help me with ur inputs

Thanks In Advance
Meva
# 4  
Old 09-19-2009
Hi,

If you want to use regex the comparison operator i the tidle:
Code:
awk 'BEGIN{f10=" ";if(f10 ~ /^[[:space:]]$/) {print "Space"}else{print "not Space"}}'

# 5  
Old 09-19-2009
hi..

let f10=""

if [[ -z $f10 ]]
then
echo blank
else
echo non-blank
fi

this will work...
# 6  
Old 09-19-2009
I think the OP wants a awk solution.
# 7  
Old 09-23-2009
Yes you are right!!! awk output is required...

but when i tried with the below piece of code

Code:
 ls sample.txt | awk '
  { a[NR]=$1 }
  END{
  FS="n"
  for(i=1;i<=NR;i++)
     {
            while( getline < a[i] ) 
		{
 	           f1=$0;
  	           print("Line::",f1);  
                        f2=substr(f1,1,1)     
                        print("Field1::",f2);
                        f3=substr(f1,2,1)
                        print("Field2::",f3);
                        f4=substr(f1,3,6)
                        print("Field4::",f4);
                        f5=substr(f1,9,2)     
                        print("Field5::",f5);
                        f6=substr(f1,11,58)
                        print("Field6::",f6);
                        f7=substr(f1,69,17)     
                        print("Field7::",f7);
                        f8=substr(f1,86,11)
                        print("Field8::",f8);
                        f9=substr(f1,97,1)     
                        print("Field9::",f9);
                        f10=substr(f1,98,7)
                        print("Field10::",f10);
                        if(f10 ~ /^[[:space:]]$/){
                        print "Field 10 is Correct"}
                        else{
                         print "Field 10 is Wrong"}
                        f11=substr(f1,105,21)     
                        print("Field11::",f11);
                        f12=substr(f1,126,15)
                        print("Field12::",f12);  
                        f13=substr(f1,141,15)
                        print("Field12::",f13);         
                        f14=substr(f1,156,2)
                        print("Field13::",f14); 
	            if(f14 ~ /^[[:space:]]$/){
                         print "Field 13 is Correct"}
                        else{
                         print "Field 13 is Wrong"}
                        f15=substr(f1,158,2)
                        print("Field14::",f15); 
			} 
              }
     }'

It always gave me the output as
Quote:
Field 10 is Wrong
Field 13 is Wrong
...even when it is supposed to display Field 10/13 is Correct.

what might be the problem with my if condition...please help me on this....
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