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HI Newbi in Unix (spanish)

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# 1  
Old 09-02-2009
HI Newbi in Unix (spanish)
Mi idea es crear un pequeña shell...lo que pasa es que cuando ejecuto el siguiente programa va todo bien hasta que me salta el error
perror("Error al ejecutar la función execvp\n");
Entonces la aplicación me entra en un bucle(repitiendo todo el rato el error anterio), como puedo hacer para que eso no pase.

#include <iostream>
#include <unistd.h>
#include <cstring>
#include <sys/wait.h>

using namespace std;

const int MAX_ELEMENTOS=12; //De esta manera limitamos un numero maximo de "comandos", en este caso lo limitamos a 12.

void trocear_linea(char *, char *[]); //Utilizaremos esta funcion para dividir la linea de comandos que nosotros le metemos.

int main()
{
char cadena[100];
char *lista_elementos[MAX_ELEMENTOS];

pid_t pid; //Declaramos la variable pid.

cout<<"PROMPT-MI-SHELL: "; //Este es el mensaje que aparecera al ejecutar el programa, es decir el prompt.
cin.getline(cadena,100); //Leemos el prompt, y lo introducimos en la cadena que luego trocearemos.

trocear_linea(cadena,lista_elementos); //Troceamos la linea de comandos que previamente le hemos introducido.

while (strcmp(lista_elementos[0],"salir")!=0)
{
pid=fork(); //Creamos un proceso hijo.

if(pid==0) //Evaluamos el pid del hijo y entonces ejecutamos el comando.
{
if (execvp(lista_elementos[0], lista_elementos)==-1)
{
perror("Error al ejecutar la funcion execvp\n"); //Este error aparecerá cuando introduzcamos comandos erroneos.

}
}
else
{
wait(NULL); //Si el pid es el del padre, este esperará hasta que termine el proceso hijo.
cout<<"PROMPT-MI-SHELL: "; //Este es el mensaje que aparecera al ejecutar el programa, es decir el prompt.
cin.getline(cadena,100); //Leemos el prompt, y lo introducimos en la cadena que luego trocearemos.

trocear_linea(cadena,lista_elementos); //Troceamos la linea de comandos que previamente le hemos introducido.

}


}

cout<<"El programa ha terminado";

}

void trocear_linea(char *linea, char *lista_elementos[])
{
char *elemento;
const char DELIMITADOR[]=" \t"; //Espacio en blanco o tabulador.
int num; //Número de elementos.

num=0;
while (linea!=NULL && num<MAX_ELEMENTOS)
{
elemento=strsep(&linea,DELIMITADOR);
if (strcmp(elemento,"")!=0)
{
lista_elementos[num]=elemento;
num++;
}
}
lista_elementos[num]=NULL;
}
# 2  
Old 09-02-2009
Hello.

Per our forum rules, all posts must be in English.

We do provide translation services for posts from English to a number of languages as a benefit to users. However, posts must be in English.

Please repost in English.

Thank you for your cooperation.

The UNIX and Linux Forums.
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