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if else error

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# 1  
Old 08-28-2009
if else error
Why the following script shows error ???

Code:
#!\bin\bash

echo -n "Enter number1 : "
read num1
echo -n "Enter number2 : "
read num2
read -n "Enter number3 : "
read num3
if [ "$num1" -gt "$num2" -a "$num1" -gt "$num3" ]
then
    echo "first number is bigger"
elif [ "$num2" -gt "$num1" -a "$num2" -gt "$num3" ]
then 
    echo "2nd number is bigger"
elif [ "$num3" -gt "$num1" -a "$num3" -gt "$num2" ]
then 
    echo "3rd num is bigger"
else
    echo "all are equal"
fi

While executing, the error is like this..

Quote:
asit@asit-desktop:~/script$ source ifdemo.sh
Enter number1 : 100
Enter number2 : 200
bash: read: Enter number3 : : invalid number
# 2  
Old 08-28-2009
Houps....

Replace
Code:
read -n "Enter number3 : "

by
Code:
echo -n "Enter number3 : "

# 3  
Old 08-28-2009
Check that line:

Quote:
Originally Posted by lipun4u
Code:
#!\bin\bash

echo -n "Enter number1 : "
read num1
echo -n "Enter number2 : "
read num2
read -n "Enter number3 : "
read num3
if [ "$num1" -gt "$num2" -a "$num1" -gt "$num3" ]
then
    echo "first number is bigger"
elif [ "$num2" -gt "$num1" -a "$num2" -gt "$num3" ]
then 
    echo "2nd number is bigger"
elif [ "$num3" -gt "$num1" -a "$num3" -gt "$num2" ]
then 
    echo "3rd num is bigger"
else
    echo "all are equal"
fi

# 4  
Old 08-28-2009
thanx everybody

that was a silly mistake
# 5  
Old 08-28-2009
and remove the " around the var...
# 6  
Old 08-28-2009
And correct your shebang:

Code:
#!\bin\bash

Smilie
# 7  
Old 08-28-2009
why ?
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