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Run multiple commands in $() without opening a new shell

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Top Forums Shell Programming and Scripting Run multiple commands in $() without opening a new shell
# 1  
Old 08-27-2009
Data Run multiple commands in $() without opening a new shell
The code below works, but takes too many lines and looks awkward:

Code:
        db2 "export to $filename of del select * from $table with ur"|tee -a $LOGFILE|awk '/Number of rows exported:/ {print $5}' > numrows.tmp
        numrows=$(cat numrows.tmp)
        rm numrows.tmp

When I try the statement below instead, I get a message saying there's no connection to the database. That's because it opened a new shell. It's opening a new shell when I give more than just the db2 command. How can I get the code below work:

Code:
numrows=$(db2 "export to $filename of del select * from $table with ur"|tee -a $LOGFILE|awk '/Number of rows exported:/ {print $5}' )


Thanks in advance
Naveen
Last edited by Franklin52; 08-27-2009 at 04:42 PM.. Reason: Please use code tags!
# 2  
Old 08-27-2009
You can read the value like this:

Code:
db2 "export to $filename of del select * from $table with ur"|tee -a $LOGFILE|awk '/Number of rows exported:/ {print $5}' | read numrows

# 3  
Old 08-27-2009
numrows variable is not getting anything assigned by read.
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