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cat file_list | [script to print last some characters]

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# 1  
Old 08-25-2009
cat file_list | [script to print last some characters]
Hello guys,

I have a list of files. For example:

Code:
/disk1/mediator_home/tmp/ntest/TSFILE00.8256.GGG1-U.0908250009.unp.20090824P8.is
/disk1/mediator_home/tmp/ntest/TSFILE00.8257.GGG1-U.0908250013.unp.20090825P1.is
/disk1/mediator_home/tmp/ntest/TSFILE00.8257.GGG1-U.0908250013.unp.20090824P8.ic
/disk1/mediator_home/tmp/ntest/TSFILE00.8256.GGG1-U.0908250009.unp.20061116P1.is
/disk1/mediator_home/tmp/ntest/TSFILE00.8257.GGG1-U.0908250013.unp.20090825P1.ic
/disk1/mediator_home/tmp/ntest/TSFILE00.8256.GGG1-U.0908250009.unp.20321116P1.is
/disk1/mediator_home/tmp/ntest/TSFILE00.8257.GGG1-U.0908250013.unp.20090824P8.is
/disk1/mediator_home/tmp/ntest/TSFILE00.8257.GGG1-U.0908250013.unp.20061116P1.is
/disk1/mediator_home/tmp/ntest/TSFILE01.2009.08.23.00181910.unp.20090823P1.ic
/disk1/mediator_home/tmp/ntest/TSFILE01.2009.08.23.00111909.unp.20090823P1.ic
/disk1/mediator_home/tmp/ntest/TSFILE01.2009.08.23.00111909.unp.20090822P8.ic
/disk1/mediator_home/tmp/ntest/TSFILE00.8256.GGG1-U.0908250009.unp.20090825P1.is
/disk1/mediator_home/tmp/ntest/TSFILE00.8254.GGG1-U.0908250002.unp.20090824P8.is
/disk1/mediator_home/tmp/ntest/TSFILE01.2009.08.23.00051908.unp.20090822P8.ic
/disk1/mediator_home/tmp/ntest/TSFILE01.2009.08.23.00051908.unp.20090823P1.ic
/disk1/mediator_home/tmp/ntest/TSFILE00.8255.GGG1-U.0908250005.unp.20090824P8.is

I need to get list of unique characters from the last, like this:
substring (s, length(s) - 13, 10)

For example: above output is:

Code:
20061116P1
20090822P8
20090823P1
20090824P8
20090825P1
20321116P1

Please help,

Thanks in advance
# 2  
Old 08-25-2009
Code:
awk -F"." '{ if (NF>0) print $(NF - 1)  }' file | sort -u

# 3  
Old 08-25-2009
try this also...
awk -F"/" '{ print $6 }' test_file | sed 's/-/./g' | awk -F"." '{ print $7 }' | sort |uniq



20061116P1
20090822P8
20090823P1
20090824P8
20090825P1
20321116P1
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