how to delete duplicate rows based on last column


 
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# 8  
Old 08-25-2009
Question

Its not exactly working..
To tell
My data has different values in the first column not all are same as i had mentioned in question &
data in my file looks some what lik this
Code:
1900  2  7  0   9.5000  76.5000 4.30
1900  2  7  0   9.5000  76.5000 6.00
1901  2 15  0  26.0000 100.0000 6.00
1901  4 27  0  12.0000  75.0000 5.00
1901  4 17 21  40.0000  71.0000 5.90
1902  4 17 21  40.0000  71.0000 5.90
1902  8 12 17  39.5000  68.5000 6.20
1902  8 22  3  40.0000  77.0000 8.60
1902  8 22  3  40.0000  76.5000 8.20
1902  8 22  3  40.0000  76.5000 8.30
1902  8 22  3  40.0000  77.0000 8.20
1903  8 30 21  37.0000  71.0000 7.70
1904  9 20  6  38.5000  67.0000 6.30

The output which i need is exactly lik this....

Code:
1900  2  7  0   9.5000  76.5000 6.00
1901  2 15  0  26.0000 100.0000 6.00
1901  4 27  0  12.0000  75.0000 5.00
1901  4 17 21  40.0000  71.0000 5.90
1902  8 12 17  39.5000  68.5000 6.20
1902  8 22  3  40.0000  77.0000 8.60
1902  8 22  3  40.0000  76.5000 8.30
1903  8 30 21  37.0000  71.0000 7.70
1904  9 20  6  38.5000  67.0000 6.30


Last edited by vgersh99; 08-25-2009 at 10:21 AM.. Reason: code tags, PLEASE!
# 9  
Old 08-25-2009
To keep the forums high quality for all users, please take the time to format your posts correctly.

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# 10  
Old 08-25-2009
Reva,

it's working properly for me , of course with sort a you can make the sequence in order.

something like this :
Code:
awk '{ va2=$NF;va1=$(NF-1);va=$(NF-2);$NF="";$(NF-1)="";$(NF-2)="";if ($0 in a) { if (va" "va1" "va2 >a[$0] ){a[$0]=va" "va1" "va2}} else {a[$0]=va" "va1" "va2}} END { for ( i in a ) print i" "a[i] }'  file_name.txt | sort +1n


Last edited by panyam; 08-25-2009 at 11:10 AM..
# 11  
Old 08-26-2009
ya i will follow from next post...

---------- Post updated 08-26-09 at 04:34 AM ---------- Previous update was 08-25-09 at 08:49 AM ----------

Thanks for the help i got it...

---------- Post updated at 04:45 AM ---------- Previous update was at 04:34 AM ----------

Hiii
now if i have data like shown below.how to sort it out. i mean delete duplicate entries in such a way that it must take the largest value in last column & it must choose a row which has many sets of values in the row.
For example the data in my file is
HTML Code:
1900  2  7  0   9.5000  76.5000 0.00 4.30 0.00 0.00 0.00 4.30
1900  2  7  0  10.8000  76.8000 0.00 6.00 0.00 0.00 0.00 6.00
1901 12  1  0  37.8000  66.0000 0.00 5.00 0.00 0.00 0.00 5.00
1901 12  1  0  37.8000  66.0000 0.00 4.60 3.00 3.50 3.50 4.60
1902  4 17 21  40.0000  71.0000 0.00 5.80 0.00 5.90 5.70 5.90
1902  8 12 17  39.5000  68.5000 0.00 6.00 0.00 6.20 5.90 6.20
1902  8 22  3  40.0000  77.0000 0.00 0.00 0.00 8.00 8.60 8.60
1902  8 22  3  40.0000  76.5000 0.00 0.00 0.00 0.00 8.20 8.20
1902  8 22  3  40.0000  76.5000 0.00 0.00 0.00 0.00 8.30 8.30
1903  5 16  6   5.3600  80.0000 0.00 4.50 0.00 5.00 0.00 5.00
1903  5 16  6   5.3600  80.0000 0.00 4.30 0.00 3.00 0.00 4.30
The output for it is
HTML Code:
1900  2  7  0  10.8000  76.8000 0.00 6.00 0.00 0.00 0.00 6.00
1901 12  1  0  37.8000  66.0000 0.00 4.60 3.00 0.00 3.50 4.60
1902  4 17 21  40.0000  71.0000 0.00 5.80 0.00 5.90 5.70 5.90
1902  8 12 17  39.5000  68.5000 0.00 6.00 0.00 6.20 5.90 6.20
1902  8 22  3  40.0000  77.0000 0.00 0.00 0.00 8.00 8.60 8.60
1903  5 16  6   5.3600  80.0000 0.00 4.50 0.00 5.00 0.00 5.00
Here it removes duplicates & checks for longest row with many values & largest value in last column.
If any one has an idea help me out..

Last edited by reva; 08-26-2009 at 12:06 PM..
# 12  
Old 08-26-2009
From where you got :

Code:
1901 12  1  0  37.8000  66.2000 0.00 4.60 3.00 0.00 3.50 4.60

in the output you mentioned.


I hope with the code that we have given you can try further a bit to achieve your task.
# 13  
Old 08-26-2009
ya i have corrected my output just check now once..

Last edited by reva; 09-01-2009 at 12:35 AM..
# 14  
Old 09-01-2009
If i have 19 columns & i need to just check duplicates for column 1,2,3,4 & tak the largest value of column 18.Then how to use awk..help me out & try explaining the code also i am very new to unix to tell.
Thanks in advance
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