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write script for previous date

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# 1  
Old 08-18-2009
Data write script for previous date
Hi all,
I need to write a unix shell script that will return the previous date of date entered and i have to consider leap year also.

For eg:- if i entered 2009-08-18 then the script should return 2009-08-17

can you please help me to write this script.???Image
# 2  
Old 08-18-2009
Quote:
Originally Posted by prasson_ibm
Hi all,
I need to write a unix shell script that will return the previous date of date entered and i have to consider leap year also.

For eg:- if i entered 2009-08-18 then the script should return 2009-08-17

can you please help me to write this script.???Image
Did you tried any code..?
then we can see what approach u r using..
# 3  
Old 08-18-2009
Code:
#!/bin/ksh
timestamp=$(printf "%(%Y-%m-%d+%H:%M:%S)T" now) 
timeint=$(printf "%(%#)T" "$timestamp") 
((daysec=24*60*60)) 
((yesterday=timeint - daysec)) 

printf "yesterday %(%Y-%m-%d)T \n" "#$yesterday"

# 4  
Old 08-18-2009
Thanks for your reply, but can you please explain me what you doing in this script.
My requirment is to pass the date as the parameter and script should return the previous date
# 5  
Old 08-18-2009
add after 1st line, call script using date format yyyy-mm-dd
Code:
timestamp=$(printf "%(%Y-%m-%d+%H:%M:%S)T" now) 
[ "$1" != "" ] && timestamp=$(printf "%(%Y-%m-%d+%H:%M:%S)T" "$1+00:00:00")

# 6  
Old 08-18-2009
hi, thanks for your reply,i m trying to run this script on AIX box,but getting error...SmilieSmilie
# 7  
Old 08-18-2009
Need ksh93.
ksh Software Download Package List
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