Shell Programming and Scripting

Hi,

Can anyone please help me ascci to decimal conversion in bash

I have a file which contains stream of numbers like this,these are ascci values


729711810132973278105991013268971213233

I want to covert it to its actual value like upper code's decimal is

"Have a Nice Day!"

Thanks In advance
Sunil

The correct spelling is "ascii". See "man ascii".
What software are you using to view the file which produces the character record you describe?
Recording characters as two-digit? decimal is much too weird. Can you post a definitive unix hexadecimal dump af a couple of records such that the bit pattern of the data is 100% clear.

And just how did you figure out that out ?

You'll need to add a separator character (space or comma etc.) to delimit individual ASCII decimal values. Otherwise it's difficult to build the string from your input data.

tyler_durden

Can you provide sample input and sample output with an explanation of the process required to convert input to output? Then we can consider code for the conversion.

I can giv u logic.

we have only 1st chracter to control the flow,else we cant handle..

letc consider ascii values 1st

[A-Z]=[65-96]
[a-z]=[97-132]
and special characters like space=32 etc..

so if 1st character is 1 then we have to read 3 charaters continusly then assign this value to a valiable and print its decimal value

then read 4th character and check if its 1 again same logic,

in case its not one we have to read 2 characters and and print its decimal value..and so on till EOF

Did any one get any idea of my logic or correct me if any one has any thing else suggest?

--------------------------------------------------------------------------------

Methyl sample code for u..
a file contails a values (acsii) like this
65666768

I have to read the file and convert these values in its actual values
so out put of above should be
ABCD

exsample 2
729711810132973278105991013268971213233
Have a Nice Day!


Note: there may be special chacters too ,for e$xample "!" in upper example

If any one can giv me code for vice versa of it i.e. changing simple text of decimal to ascii, it wud be appreciated

eg:Have a Nice Day!
729711810132973278105991013268971213233

(IMHO. This is interesting but impossible).

Almost everything is possible , try this:

Code:

awk '{
  for(i=1;i<=length;i+=2){
    if(int(substr($0,i,2)) < 20) {
      printf("%c",int(substr($0,i,3)))
      i++
    }
    else {
      printf("%c",int(substr($0,i,2)))
    }
  }
}
END{print ""}'

This is what I get:

Code:

$ echo '729711810132973278105991013268971213233' |
awk '{
  for(i=1;i<=length;i+=2){
    if(int(substr($0,i,2)) < 20) {
      printf("%c",int(substr($0,i,3)))
      i++
    }
    else {
      printf("%c",int(substr($0,i,2)))
    }
  }
}
END{print ""}'
Have a Nice Day !
$

Regards