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How to format columns using AWK

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# 8  
Old 07-25-2009
Code:
xx='Mark J Walton 145-852-252            Acct'
echo $xx  | sed 's/ \([[:digit:]]\)/|\1/; s/\([[:digit:]]\) /\1|/'

# 9  
Old 07-25-2009
What's wrong with the solutions of danmero?
Last edited by Franklin52; 07-25-2009 at 01:45 PM..
# 10  
Old 07-25-2009
I dont see any thing wrong with Danmero's solution. I fact I think it might be more flexible and goingforth that might give the solution than mine.
Right now itisnotthebest.
Try this:
Code:
xx='Mark J Walton 145-852-252            Acct Department'
echo $xx  | awk '{a=$(NF-1);b=$NF;$(NF-1)=$NF="";printf "%s%20s%10s\n",$0,a,b}'

Output:
Code:
Mark J Walton 145-852-252                  AcctDepartment

And this:
Code:
xx='Mark J Walton 145-852-252            Acct Department'
echo $xx  | sed 's/ \([[:digit:]]\)/|\1/; s/\([[:digit:]]\) /\1|/'

output:
Code:
Mark J Walton|145-852-252|Acct Department

# 11  
Old 07-25-2009
Hi, All -

Thanks for all your help. I just wanted to see the creative use of SED in this situation.

Thanks again for all your help. I have learned a lot while solving this issue.
# 12  
Old 07-25-2009
The 2nd solution of danmero meet the needs of what the OP wants (check the first post). This is what I get:

Code:
$ cat file
John Roberts 324-141-984 Acct
Jack Williams 159-555-555 Acct
William Jackson  949-911-888 Acct
Mark J Walton 145-852-252            Acct
Fred P Milton 483-244-390                Acct
Bill P J Miller                 404-050-223  Acct
$
$ awk '{a=$(NF-1);b=$NF;$(NF-1)=$NF="";printf "%s%20s%10s\n",$0,a,b}' file
John Roberts           324-141-984      Acct
Jack Williams           159-555-555      Acct
William Jackson           949-911-888      Acct
Mark J Walton           145-852-252      Acct
Fred P Milton           483-244-390      Acct
Bill P J Miller           404-050-223      Acct

Am I missing something?
# 13  
Old 07-25-2009
No, I dont think u r missing anything.
I posted my code because "ora_umair" asked for it.
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