Shell Programming and Scripting

find use prevstamp, if you not have it, you must create the first. You can set timestamp as you like, 200101... is only example. Example you don't like to look old logs, starting from just now:
touch prevstamp
is good solution.

Try this:

Code:

ls -1tr | sed -n '1,/^lastlog.txt$/! p' > newlog.txt
mv newlog.txt lastlog.txt

You have the list of latest files lastlog.txt
Do your usual email procedure.

This makes sense edidataguy but if the log gets created then we can do ls -ltr /abc/def/abcd_yymmdd.log .
Compare and move it to new log and then move old lo to new log .
Incase the log does not gets created then the script which will be running through cron each 10 minutes will give an error each time it does not find a log .
Scenario is the log files will be created randomly 3-4 at a time when application triggers and it may not get generated at all for 2-3 days .

@yogi90 : you didn't provide the time format.

I am assuming it is HH_MM

Code:

$ls -1
abc2008_07_22_13_25.log
abc2009_07_22_12_23.log
abc2009_07_22_13_25.log
abc2009_07_21_11_25.log

$sort -t'_' -k1.4,1.7 -k2.1,2.2 -k3.1,3.2 -k4.1,4.2 -k5.1,5.2 | tail -1
$abc2008_07_22_13_25.log

I wish I understood the requirement correctly.

The log file will always be created, provided the log file already exists.
If you list and no files exist, then a 0 byte file will be created.
Try this:

Code:

echo "bla bla bla" > oldlog.log
ls -l oldlog.log

output

Code:

-rw-r--r--  1 admin None        12 Jul 23 13:25 oldlog.log

Now try this:

Code:

 ls -1 idontexist* > oldlog.log
ls -l oldlog.log

output

Code:

-rw-r--r--  1 admin None        0 Jul 23 13:25    oldlog.log

If you want in your code check for [[ -s oldlog.log ]]

#!/usr/bin/ksh

###############################################################################
# #
#-----------------------------------------------------------------------------#
# Shell Script Name : getlogs #
# #
# Location (directory) : /usr/local/bin #
#-----------------------------------------------------------------------------#
# #
# #
###############################################################################

#typeset -u export SID=$1
#typeset -l export sid=$1

Hostname=$(hostname)

usermail="abcd @pqrst.com"

ls -1tr /dir1/dir2/abcd*.log | sed -n '1,/^lastlog.txt$/! p' > newlog.txt

mv newlog.txt lastlog.txt

sleep 30

/usr/bin/mailx -s "${HOSTNAME}: Subject" $usermail < $/dir1/dir2/newlog.txt

edidataguy if I use this it will always send a zero byte file to user which I do not want , I need to send the log file only when it gets created sometimes otherwise do not send anything

find logs modified ten minutes ago. just modify your script accordingly. if there is nothing found then there are no log files generated within 10 minutes timeframe then don't send email.

Code:

find . -name "*.log" -mmin +10