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extracting part of a text file

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# 8  
Old 07-22-2009
hi guys
Thanks for your replies so far

This pattern doesnt do anything :
sed -n '/^12:00/,/^12:03/p' event.log > new_event.log

And the grep ones I believe will only extract lines that contain the pattern that I have entered. But they would miss the lines in between. I do need the lines without the pattern as well.

I again summarise my requirement:
In a file extract every thing from the first occurance of pattern: 12:01:00 till the last occurance of pattern: 12:03:00.

many thanks
ali
# 9  
Old 07-23-2009
I have no issues.
Is it possible your input file is DOS formatted?

Here is my working.
Code:
cat event.log
12:00:07 event 0 happened.
some line at 2
12:01:01 event 1 happened.
some line at 4
12:01:05 event 2 happened.
12:01:30 event 3 happened.
some line at 7
some line at 8
12:02:01 event 4 happened.
12:02:40 event 5 happened.
12:03:40 event 6 happened.
12:04:06 event 6 happened.

Command:
Code:
sed -n '/^12:00/,/^12:03/p' event.log

Output:
Code:
12:00:07 event 0 happened.
some line at 2
12:01:01 event 1 happened.
some line at 4
12:01:05 event 2 happened.
12:01:30 event 3 happened.
some line at 7
some line at 8
12:02:01 event 4 happened.
12:02:40 event 5 happened.
12:03:40 event 6 happened.

May be version issues?
Remove the "> new_event.log" part and check.
# 10  
Old 07-23-2009
PHP
Quote:
Originally Posted by alinaqvi90
I want to extract every thing in that file listed between a given start time and an end time.
.....
so some thing like all events between
the first entry of 12:01:00 and the last entry of 12:03:59

...and store them in a random text file. Note time stamps can be repeated and therefore I mentioned the first and the last entries.

And not all lines in the log file start with a time stamp.
Did you ever try my previous solution
# 11  
Old 07-23-2009
Quote:
Originally Posted by alinaqvi90
hi guys
Thanks for your replies so far

This pattern doesnt do anything :
sed -n '/^12:00/,/^12:03/p' event.log > new_event.log

And the grep ones I believe will only extract lines that contain the pattern that I have entered. But they would miss the lines in between. I do need the lines without the pattern as well.

I again summarise my requirement:
In a file extract every thing from the first occurance of pattern: 12:01:00 till the last occurance of pattern: 12:03:00.

many thanks
ali
Try with a gap before the "p" like this.
Code:
sed -n '/^12:00/,/^12:03/ p' event.log > new_event.log
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