Shell Programming and Scripting

Code:

 
Hi Friends,
 
How to list todays file from a directory listing of files for amny dates.
 
I tried with the following options but not working :
 
find . -name "esi01v*" -mtime 1 -ls
 
find . -name "esi01v*" -ctime 1 -ls
 
find . -name "esi01v*" -mtime 1
 
Please advise

Try:

Code:

find . -type f -mtime 1 -exec ls {} \+

please tell me where do I give the pattern like abcd* or esi001*

something like this :

Code:

find . -name "esi01v*"  -type f –ctime 0 | xargs ls -l

Hi Panyam,

I tired but it is listing yesterdays files also

tried with -ctime with 0 1 etc but not the correct results

then modify that script a bit...

Code:

find . -name "esi01v*" -type f -mtime 1 -exec ls {} \+

HI Rakesh,

afraid...not working. itried other options in the above command line as well but not getting the desired results.

is there anyway i can match todays date Jul 17 with the ls -lrt command date and extract file

like :
date | awk '{print $2}' | cut -c 1-3 > this command will return Jul
date | awk `{print $3}` > will return 17

ls -lrt esi01v* | awk '{print $6 $7}' > will return Jul 17

is it possible to concatenate the first 2 match with the 3rd and list files