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Replace 9-16 positions of a text file.

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# 1  
Old 07-16-2009
Replace 9-16 positions of a text file.
Hi

i am having text file like this


40000201040005200213072009000000700000050744820906904421
40069300240005200713072009000000067400098543630000920442

i want to replace 9-16 positions of my txt file...by 1234567...in a single line command

i.e
0400052....should be replaced by 1234567

2400052 ....should be replaced by 1234567

Thanks in advance
# 2  
Old 07-16-2009
A sed command could help
Code:
 sed 's/^\(.\{8\}\).\{7\}\(.*\)/\11234567\2/' yourfile.txt

# 3  
Old 07-16-2009
one in awk :

Code:
awk '{ print substr($0,1,8)"1234567"substr($0,16)}' file_name.txt

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