10 More Discussions You Might Find Interesting
1. UNIX for Beginners Questions & Answers
Hello All,
Hope you're doing well !
I am trying below command to be passed in a shell script, header_date_14 is a variable and $1 is the name of a file I intend to pass as a command line argument, however command line argument is not being accepted.
header_date_14=$(m_dump... (8 Replies)
Discussion started by: ektubbe
8 Replies
2. Shell Programming and Scripting
i want to copy the command
awk -F "=" '{print $2}'
in a user defined variable for later/multiple use...
Please let me know how to do that.. (11 Replies)
Discussion started by: shreedhar.rk123
11 Replies
3. Shell Programming and Scripting
I am working with a sh script on a solaris 9 zone (sol 10 host) that grabs information to build the configuration command line. the variables Build64, SSLopt, CONFIGopt, and CC are populated in the script. the script includes
CC=`which gcc`
CONFIGopt=' --prefix=/ --exec-prefix=/usr... (8 Replies)
Discussion started by: oly_r
8 Replies
4. Shell Programming and Scripting
Hello,
First post for Newbie as I am stumped. I need to get certain elements for a specific PID from the ps command. I am attempting to pass the value for the PID I want to retrieve the information for as a variable. When the following is run without using a variable, setting a specific PID,... (3 Replies)
Discussion started by: Coyote270WSM
3 Replies
5. Shell Programming and Scripting
Hi,
I am trying to do the following thing
var='date'
$var
Above command substitutes date for and in turn runs the date command and i am getting the todays date value.
I am trying to do the same thing as following, but facing some problems,
unique_host_pro="sed -e ' /#/d'... (3 Replies)
Discussion started by: gvinayagam
3 Replies
6. Shell Programming and Scripting
For example I have variable like below
echo $OUTPUT
/some/path/`uname -n`
when I try to use the variable OUTPUT like below
cd $OUTPUT or cd ${OUTPUT}
I am getting bad substituion error message
$ cd $OUTPUT
ksh: cd: bad substitution
$ cd ${OUTPUT}
ksh: cd: bad substitution
... (1 Reply)
Discussion started by: rajukv
1 Replies
7. Shell Programming and Scripting
I am making a pipeline of several commands.
This is a part of my shell script.
array=(
"mkdir src"
"ls -l | grep tk_ > src/list"
)
len=${#array
}
i=0;
while ; do
echo ${array}
if !(${array}); then exit 1; fi;
let i++
done
---------------------------------------
"mkdir... (5 Replies)
Discussion started by: thsuk1
5 Replies
8. UNIX for Dummies Questions & Answers
I know this script is crummy, but I was just messing around.. how do I get sed's insert command to allow variable expansion to show the filename?
#!/bin/bash
filename=`echo $0`
/usr/bin/sed '/#include/ {
i\
the filename is `$filename`
}' $1
exit 0 (8 Replies)
Discussion started by: glev2005
8 Replies
9. Shell Programming and Scripting
I want to instert Category:XXXXX into the 2. line
something like this should work, but I have somewhere the wrong sytanx. something with the linebreak goes wrong:
sed "2i\\${n}Category:$cat\n"
Sample:
Titel Blahh Blahh abllk sdhsd sjdhf
Blahh Blah Blahh
Blahh
Should look like... (2 Replies)
Discussion started by: lowmaster
2 Replies
10. UNIX for Dummies Questions & Answers
I'm having an issue when I export within my program. I'm getting the variable name, not the variable value. I have a configuration file (config.txt) that has the values of the variables set as so:
set -a
export ARCHIVEPOSourceDir="/interfaces/po/log /interfaces/po/data"
export... (2 Replies)
Discussion started by: ParNone
2 Replies
