Shell Programming and Scripting

Hi all, im doing this script in which i read from a logfile line by line, my problem is this:

The script was working fine until i added this statement to SSH into another machine to look for some data, it enters and retrieves the data just fine, but for some strange reason after it goes thru the case statement it exits the loop as if there was nothing else to be read from the file... if you remove this ssh statement it doesnt match anything on the case statement AND it actually continues to read the next line...

Code:

echo $LINE | grep -i "transition to ok"
if [ $? -eq 0 ]
then
DIMMR=`ssh root@20.0.0.4 "ssh module-$CURRMOD \"ipmitool sel get 0x$HEXREG\"" | grep -i "event data" | cut -d: -f2 | cut -c2-7`
echo "A replacement of DIMM $DIMMR has ocurred"
fi

case $DIMMR in

"000011")   A1=0 ;;
"000012")   A2=0 ;;
"000021")   B1=0 ;;
"000022")   B2=0 ;;
"000031")   C1=0 ;;
"000032")   C2=0 ;;
"000041")   D1=0 ;;
"000042")   D2=0 ;;
esac

echo $A1
echo "---------------------------------------------------------------------------------"

done < /tmp/mfg/ecclog.txt

I'm not sure how to get around this, perhaps something i missed in the case? or one of those hideous subshell weird behaviours due to the SSH?

i attached the files for you to see, thank you.

Oh boy... am i stupid.... i swear i did searched but i could not find anything like it, right after posting it showed me a list of related threads and there is was exactly what i was looking for:

https://www.unix.com/shell-programmin...hile-loop.html

Apparently this is caused by the ssh reading my file and not leaving anything for the while loop...

Anyway, thanks for you time guys