Shell Programming and Scripting

Hi,

I have a requirement where i need to replace 3 backslashes with 2 in the below mentioned string, but i am facing problem with backslashes. However i tried the option below but doesnt work. My input remains a constant as i receive it from my upstream.

Input String= "-rfile \\\landingzone-dev\VALDEV\CI"

My code:

Code:

#!/bin/sh
var="-rfile \\\landingzone-dev\VALDEV\CI"
    dir=`echo $var | sed 's/\\\\/\\\\/g'`
    echo $dir

Current Output:
-rfile \landingzone-dev\VALDEV\CI

Desired Output:
-rfile \\landingzone-dev\VALDEV\CI

Any inputs would be reallly helpful.

Thanks in advance,
KK

Code:

#!/bin/sh
var='-rfile \\\\\landingzone-dev\VALDEV\CI'
echo "var->[${var}]"
dir=`echo "$var" | sed 's#\\\\#\\\#'`
echo "dir->[${dir}]"

But my input is always a constant, i want the desired O/p but keeping
var="-rfile \\\landingzone-dev\VALDEV\CI"
as the variable value.
Is there any way to acheive it by keeping the above value to the vriable?

set variable in single qoute

Code:

X='-rfile \\\landingzone-dev\VALDEV\CI'
echo $X

-rfile \\landingzone-dev\VALDEV\CI