Shell Programming and Scripting

Hi,

I know removing whitespaces I can found so many threads to read how it works and i did it, but my problem isn't solved...

I have in my script a variable $1 which can contains a text like " Channel ".

No I want to check if $1 contains the word Channel, but I don't know how many whitespaces there are before and after the word...

I tried this:

if [ "Channel" = $1|awk '{print $1}'>$1 ] ; then
echo "found!!!"
fi

So where is the problem??
Sorry for this stupid question

Ben Sky

Hi,

Might be a bit nasty, but what if you first strip of the whitespaces?

I know there are better ways to do this, but at least is a solution.

a=`echo $1 | sed s/\s+//`

Regs David

David,
try:
a=`echo $1`


Bensky,
your if statement is a mess.

First, in a statement like
if [ ... ] ; then
you cannot put pipelines inside the braces unless the pipeline is inside backticks or something.

And a pipeline must connect commands line this " ps -ef | more". $1 is not a command.

If $1 was " command " as you said, > $1 would send the output of the awk command into a file called command.

I've been staring at your if statement for 10 minutes and I still can't figure out what you're trying to do. I assume that you want to both perform a test and have a cool side effect all in one fell swope. But I don't know what side effect you're looking for.

You should consider switching to ksh so that you can use
if [[ .... ]] ; then

Hi


David I tested your statement, and it works, if i do this in the prompt, but if I include this in my script it doesn't work:

a=`echo $1 | sed s/\s+//`
echo "!${a}!"

there are still whitespaces...

also with the version from Perderabo I have this problem...

What I'am trying to do is, to test if the content of the variable $1 is "Channel" or not...
I hope soon my coding gets better, so that it is more clear what I like to do..

Ben Sky

Hi,

I found the error..

I had set the
IFS="|" so that than the echo also printed out the whitespaces...

Thanks for your help

Ben Sky