Shell Programming and Scripting

I am trying to write a shell script using awk which will format the output of the "ps -eaf" command by sorting it by user and then listing all of the processes for each user. Here is an example of the output I want:

Here is the code I have:

Code:

#! /bin/sh

for I in `ps -eaf h | awk '{print $1}' | sort | uniq`
do
    echo "USER = $I"
    ps -eaf h | awk '/$I/ {print $2 $8 $6}'
done

The first command(`ps -eaf h | awk '{print $1}' | sort | uniq`) gets the list of user names. The second command using awk is where I'm having trouble. It is replacing "$I" with the appropriate username but it does not print anything. I've tried a few variations using awk, but have not had any luck. Any help is appreciated.

for passing variable in awk, the method is...

Code:

awk -v var="$i" '{print var}' file
or
awk '{print var}' var="$i" file

This is what I tried to use:

Code:

ps -eaf h |awk -v var="$I" '/var/{print $2 $8 $6}'

And this is the output I got from that..
Nothing like what I need.

Please try this ...it works fine

#!/bin/bash

for i in `ps -eaf | awk '{ print $1 }' | sort | uniq`
do
echo "USER = $i"
echo
ps -eaf | awk -v var="$i" 'BEGIN { print "PID PROGRAM TTY" } /var/ { print $2,$8,$6 }'
echo
done

see if this works...

Code:

 
ps -eaf  | grep $I | awk '{print $2 $8 $6}'

This works however, all users have the same processes as far as I can tell, it does not list the processes just for that user. Thanks for the input, i'm going to play around with this and see if I can get it working.

This oneliner worked for me.Tested in SUSE Linux

Code:

 ps -ef --noheader --sort -uid | awk ' { if ( $1 == x ) {print $2,$8,$6} else { print "USER="$1 "\nPID PROGRAM TTY\n"  $2,$8,$6 } x=$1}'