Shell Programming and Scripting

I have data that looks like this:

Code:

2002  140  40800.0060  GPS 20  C1  25477810.2305
2002  140  41100.0060  GPS 20  C1  25298056.0453

I need to get data after certain pattern.. for example if i search for C1
it should return

Code:

25477810.2305
25298056.0453

To achieve this, it should:

1) In the best scenario, if possible, it would start after the space/spaces that come after the search word, print the characters, and stop when space is found again

2) if that is not possible, other way would be to return 15 characters after the search pattern(after = the pattern itself would be excluded).

I tried with grep and sed, but could not get the results i wanted..

Thank you in advance!

Your number strings are of length 13 not 15 in the sample you provided.

Code:

sed -n  's/^.*C1\([[:blank:]]\{1,\}\)\([0-9]\{8\}\.[0-9]\{4\}\).*$/\2/p'

Code:

awk '
/C1/{
  for(i=1;i<=NF;i++){
     if($i == "C1"){
          print $(i+1)
     }
  }
}
' file

Code:

sed 's/.*C1\(.*\)/\1/'