Hi,
I have to separate a pattern from a string. Here are the details:
Pattern: number1.number2.number3.number4.number5
where, number 3,4,5 can be sinngle or double digits
number 1,2 are single digits.
Examples:
7.5.1.10.10
6.0.11.6.34
Now here is the sample string:
And here is the sed command that I am using:
The problem in the above case is if number 5 is double digit, it works fine..
If number 5 is single digit, The quotes : " is also printed..
I am confused why..
Please guide..
The above sed command on above string will give: 7.5.1.8.9"
where as 7.5.1.8.9 was expected.
Why is \(.\{1,2\}\) always double digits.. when i have specified that the character can be one or two?
Do I have to specify something like this?
\(\[0-9\]\{1,2\}\)
The following command dosent work either:
Hi,
I am sorry but I did not get your point.
Another thing I want to ask is that, what if there is no double quote, and has some other character?
I just want the sed to pick up number4,5,6 as one or two digit numbers.
What do you suggest in this case?
Brilliant..
Can you please explain this:
Thanks a lot
---------- Post updated at 06:22 PM ---------- Previous update was at 06:13 PM ----------
Hi Vgersh,
In the second example you gave, how does it ignore the double quotes? pattern=[^0-9]
This does not contain any double quotes..
Can you please explain?
Brilliant..
Can you please explain this:
Thanks a lot
---------- Post updated at 06:22 PM ---------- Previous update was at 06:13 PM ----------
Hi Vgersh,
In the second example you gave, how does it ignore the double quotes? pattern=[^0-9]
This does not contain any double quotes..
Can you please explain?
Thanks..
'pattern=[^0-9]*\([0-9.][0-9.]*\)'
'pattern=' followed by any character BUT a number ( [^0-9]) - repeated 0 or more time ( * ).
Followed by a 'capture' \(...\). The 'capture' consists of any number OR a '.' repeated 1 or more times.
Anything else not matched by a capture, gets eaten up by the trailing greedy '.*'.
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