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getting basename inside awk script

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# 8  
Old 06-26-2009
once again - why do you need to invoke an external command when you can do it all within awk natively?
# 9  
Old 06-26-2009
Quote:
Originally Posted by panyam
You can use ..the same working fine for me.

print "command" value and check wat ur getting ?..

I did n't understand the logic behind your script.

If you post input and output your expecting , then i hope you can get

more responces.

Code:
 
psg  -t "?"| awk  '{
             command=($5 ~ /^[A-Z]/)? $9:$8
             exe="basename " command " >> cmd_Name"
             system(exe)
              if (cmd_Name == "tec")
              {
                kill=1
              }
              if (kill ==1)
              {
              op=kill -9 " pid ";
              system(op)
              }
             }'

I want get the name of the process and compare to check if it is "tec" process or not if it is ,then i would kill it.

---------- Post updated at 05:19 PM ---------- Previous update was at 05:13 PM ----------
Quote:
Originally Posted by vgersh99
once again - why do you need to invoke an external command when you can do it all within awk natively?


how can we do it?
by doing natively do you mean to say using reg expression.?
# 10  
Old 06-26-2009
one way......
Code:
myPathname="/a/b/c/d/myExec"
n=split(myPathname, a, "/")
print a[n]

# 11  
Old 07-02-2009
one more way..

Code:
 
              psg  -t "?"|  awk '{
              cname=($5 ~ /^[A-Z]/)? $9:$8
              len=length(cname)
              regex="/"
              for(i=1;i<=len;i++)
              {
                  where = index(cname,regex)
                  if(where)
                  {
                       cname= substr(cname,where+1)
                  }
              }
              printf("%s \n",cname)
          }'
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