Shell Programming and Scripting

Im want to print filename inside loop .. the code im using :-


Filename_1=abc_20090623_2.csv.lk
Filename_2=def_20090623_2.csv.lk

i want to extract filename till .csv eg
Filename_1=abc_20090623_2
Filename_2=def_20090623_2

How can i do this inside the for loop

for((k=1;k<=$p;k++))
do
echo "$(eval echo \$FILENAME_$k)" .. working
filename=`echo "$(eval echo \$FILENAME_$k)"`... nt workn
echo $filename;
length=`expr "echo $filename : '.*'"` ... nt wrking
echo $length
substring=`echo "$(eval echo \$FILENAME_$k)" | cut -c1-($length-4)`
echo $substring
done

filename=`echo "$(eval echo \$FILENAME_$k)"`... nt workn

will work if you add:-
filename=`echo `eval echo \\$FILENAME_$k``...


now for your problem we can use shell variable manipulation:

cat test.txt :
Filename_1=abc_20090623_2.csv.lk
Filename_2=def_20090623_2.csv.lk


code :-

Code:

while read line
do
echo ${line%%.csv*}
done < test.txt

output
Filename_1=abc_20090623_2
Filename_2=def_20090623_2

BR

`echo`eval echo \\$FILENAME_$k`` is not wrking

examples:-

This code will work:-

Code:

filename_4=test.txt
for i in 4
do
echo $(eval  echo "\${filename_${i}}" )
done

and this also will work:-

Code:

for i in 4
do
echo `eval  echo "\\${filename_${i}}"`
done

for variables

Code:

file=`eval  echo "\\${filename_${i}}"`

or

file=$(eval  echo "\${filename_${i}}")

BR