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control is not going inside the awk ?

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Top Forums Shell Programming and Scripting control is not going inside the awk ?
# 1  
Old 06-22-2009
control is not going inside the awk ?
Hi


the control is not going inside the awk..
/u/bin/psg -t "pts/tC" |/bin/grep -e "ServTest" | /bin/grep -v "root"
run separately in the command line lists the running process..

why is the code inside the awk not being being executed?
can anyone tell what went wrong.

Code:
 
list=`/u/Test/programs`;
/u/bin/psg -t "pts/tC" |/bin/grep -e "ServTest" | /bin/grep -v "root" | awk -v mode=$0 '{
        kill = 0
        pid=$2
        uid=$1
        cmd_name=($5 ~ /^[A-Z]/)? $9:$8
        print "I am in between ffff"
        for(pgm in list)
        {
                pgm="de$pgm";
                if (pgm == cmd_name)
                {
                        kill = 1;
                }
        }
        if (kill == 1)
        {
                if (mode == "kill")
                {
                     print ("killing %s with %d \n",cmd_name,pid);
                     system("/u/bin/date>> /u/Test/Log")
                     print " " $0 >> "/u/Test/Log"
                     op="/u/bin/remsh " hn " -l " user "; u/bin/kill -9 " pid ">> "/u/Test/Log";
                     system(op)
                }
        }#end if
  }'

regards
Last edited by Anteus; 06-22-2009 at 07:10 AM..
# 2  
Old 06-22-2009
mode=$0 ###won't work
what is list?? is it an array??
echo won't work inside awk
there are many problems....
# 3  
Old 06-22-2009
Quote:
Originally Posted by vidyadhar85
mode=$0 ###won't work
what is list?? is it an array??
echo won't work inside awk
there are many problems....

ooh i am sorry about echo . my mistake. after correcting it printf is printing so it means code inside awk is executing..

why the printf inside for loop is not printing list has two lines.
why would not the mode=$3 work i am using it with the awk -v option , which provides initiation and assignment of the shell variable. so i think its fine. please correct me if i am wrong.

and list is a file containing names of programs.

regards
Last edited by Anteus; 06-22-2009 at 07:15 AM..
# 4  
Old 06-22-2009
no you can't assign $0 with -v option unless 0 is your variable name
check that with simple example
and you can't use a file just like that in awk
please read the awk man page once
# 5  
Old 06-22-2009
Quote:
Originally Posted by vidyadhar85
no you can't assign $0 with -v option unless 0 is your variable name
check that with simple example
and you can't use a file just like that in awk
please read the awk man page once
okk
yeah $0 is argv[0]

---------- Post updated at 04:04 PM ---------- Previous update was at 04:00 PM ----------

please delete this thread if you can there are lot of silly mistakes in this code..which i am seeing now..

and can you give me some links where i can find how to read contents of a file inside awk ..

thanks and regards
# 6  
Old 06-22-2009
Quote:
Originally Posted by Anteus
okk
yeah $0 is argv[0]

---------- Post updated at 04:04 PM ---------- Previous update was at 04:00 PM ----------

please delete this thread if you can there are lot of silly mistakes in this code..which i am seeing now..

and can you give me some links where i can find how to read contents of a file inside awk ..

thanks and regards
Here's something to start with!
# 7  
Old 06-22-2009
Quote:
Originally Posted by vgersh99
Here's something to start with!
I never knew to type

dablu dablu dablu dot google dot kom..

thanks for showing me a start a decade back Smilie

regards
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