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Shell Programming and Scripting

filename in loop

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# 1  
Old 06-21-2009
filename in loop
i have a

filename_1=file1.dat
filename_2=file2.dat

i want to pass the filename in a loop

for((i=1;i<=2;i++)
do
awk{print $1} $filename_$i.dat [so that the file name is filename_1.dat]
done

how should i pass the filename
# 2  
Old 06-21-2009
Code:
filename_1=file1.dat
filename_2=file2.dat
 
for((i=1;i<=2;i++))
do
  awk '{print $1}' $(eval echo \$filename_$i)
done

Quote:
[so that the file name is filename_1.dat]
But the filename is not filename_1.dat, it's file1.dat.
# 3  
Old 06-21-2009
Use this:-

Code:
for((i=1;i<=2;i++)
do
awk '{print $1}'  `eval  "echo \\${filename_$i}"`
done

Last edited by ahmad.diab; 06-21-2009 at 09:07 AM..
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