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split large file based on field criteria

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# 1  
Old 06-19-2009
split large file based on field criteria
I have a file containing date/time sorted data of the form
...
2009/06/10,20:59:59.950,XAG/USD,Q,1,1115, 14.3025,100,1,1
2009/06/10,20:59:59.950,XAG/USD,Q,1,1116, 14.3026,125,1,1
2009/06/10,20:59:59.950,XAG/USD,R,0,0, , 0,0,0
2009/06/10,20:59:59.950,XAG/USD,R,1,0, 14.1910,100,1,1
2009/06/10,20:59:59.950,XAG/USD,A,0,, 14.3011,100,1
2009/06/10,21:00:00.100,CHF/JPY,Q,0,0, , 0,0,0
2009/06/10,21:00:00.100,CHF/JPY,Q,1,0, 70.26, 60,2,2
2009/06/10,21:00:00.150,CHF/JPY,D,0, 70.14, 20,XC05, ,NYD9,US,NYA1
...

I want to split this file into exactly two files based on the the date/time criteria. The criteria is all the lines with timestamps less than and equal to 21:00:00.000 should go to 'file1' and greater than 21:00:00.000 should goto 'file2'.

I wrote a simple script using while loop reading each line and matching criteria.
The script works fine but since these files containing data are huge (gigs), the processing takes forever.

Is there a a better way (sed, awk, egrep or even split) to use this more effeciently??

Thanks.
# 2  
Old 06-19-2009
have you tried split or csplit ? check their man or info pages.
# 3  
Old 06-20-2009
Sorry, but I user awk for everything!

Code:
cat myfile | awk -F, '
  $2 ~ /^21/ { print > "file2"; next }
  { print > "file1" }
'

If you want two files based on each date...

Code:
cat myfile | awk -F, '
  { gsub( "/", "_", $1 ) }
  $2 ~ /^21/ { print > $1 "_2"; next }
  { print > $1 "_1" }
'

# 4  
Old 06-20-2009
Quote:
Originally Posted by scottn
Sorry, but I user awk for everything!
then why did you use cat? Smilie
# 5  
Old 06-20-2009
I didn't say I used awk exclusively. That would just be boring Smilie

But I see what you mean

Code:
awk -F, '
  { gsub( "/", "_", $1 ) }
  $2 ~ /^21/ { print > $1 "_2"; next }
  { print > $1 "_1" }
' myfile

Force of habit!
# 6  
Old 06-22-2009
Scottn,

thanks for your reply. It pretty much does the work. But I noticed two issues:

1) All the delimiters in the file "," are gone!

2) I see why you need to replace "/" with an "_" since files with "/" are not allowed, but the side effect of this is that the "/" in the file are replaced with "_".
Last edited by asriva; 06-22-2009 at 11:02 AM..
# 7  
Old 06-22-2009
Code:
$
$ cat data.txt
2009/06/10,20:59:59.950,XAG/USD,Q,1,1115, 14.3025,100,1,1
2009/06/10,20:59:59.950,XAG/USD,Q,1,1116, 14.3026,125,1,1
2009/06/10,20:59:59.950,XAG/USD,R,0,0, , 0,0,0
2009/06/10,20:59:59.950,XAG/USD,R,1,0, 14.1910,100,1,1
2009/06/10,20:59:59.950,XAG/USD,A,0,, 14.3011,100,1
2009/06/10,21:00:00.100,CHF/JPY,Q,0,0, , 0,0,0
2009/06/10,21:00:00.100,CHF/JPY,Q,1,0, 70.26, 60,2,2
2009/06/10,21:00:00.150,CHF/JPY,D,0, 70.14, 20,XC05, ,NYD9,US,NYA1
$
$ perl -ne 'BEGIN{open(F1,">file1"); open(F2,">file2")}
>   { split/[,:]/;
>     if($_[1] <= 20){print F1 $_} else{print F2 $_}
>   }
> END {close(F1); close(F2)}' data.txt
$
$ cat file1
2009/06/10,20:59:59.950,XAG/USD,Q,1,1115, 14.3025,100,1,1
2009/06/10,20:59:59.950,XAG/USD,Q,1,1116, 14.3026,125,1,1
2009/06/10,20:59:59.950,XAG/USD,R,0,0, , 0,0,0
2009/06/10,20:59:59.950,XAG/USD,R,1,0, 14.1910,100,1,1
2009/06/10,20:59:59.950,XAG/USD,A,0,, 14.3011,100,1
$
$ cat file2
2009/06/10,21:00:00.100,CHF/JPY,Q,0,0, , 0,0,0
2009/06/10,21:00:00.100,CHF/JPY,Q,1,0, 70.26, 60,2,2
2009/06/10,21:00:00.150,CHF/JPY,D,0, 70.14, 20,XC05, ,NYD9,US,NYA1
$
$

tyler_durden
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