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Find index of last occurence of a character within a string

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# 1  
Old 06-19-2009
Find index of last occurence of a character within a string
I need to find the index of last '|' (highlighted in bold) in awk :

|ifOraDatabase.Lastservererr<>0then|iferr_flag<>0then|end if

Please suggest a way... Thanks
Last edited by joyan321; 06-19-2009 at 12:06 PM..
# 2  
Old 06-19-2009
how about awk:
Code:
echo "|ifOraDatabase.Lastservererr<>0then|iferr_flag<>0then|end if"   |
  awk -F'|' ' x= length($0) - length($NR);  print x - 1'

# 3  
Old 06-19-2009
try this

Code:
awk -v RS="|"  '(NR<4) {x+=length($0) } END{print x+3}' inputfile.txt

BR
# 4  
Old 06-19-2009
Code:
echo '1234|56|7|890' | nawk '
function rindex(str,c)
{
  return match(str,"\\" c "[^" c "]*$")? RSTART : 0
}
{
  print rindex($0, "|")
}'

# 5  
Old 06-19-2009
Code:
awk 'BEGIN{FS=""}{ for(i=1;i<=NF;i++){ if($i=="|"){ p=i } }}END{  print p }' file

# 6  
Old 06-20-2009
Quote:
Originally Posted by joyan321
I need to find the index of last '|' (highlighted in bold) in awk :

|ifOraDatabase.Lastservererr<>0then|iferr_flag<>0then|end if

Code:
_rindex() 
{ 
    case $1 in 
        *$2*)
            idx=${1%$2*};
            _RINDEX=$(( ${#idx} + 1 ))
        ;;
        *)
            _RINDEX=0;
            return 1
        ;;
    esac
}

Code:
$ _rindex '|ifOraDatabase.Lastservererr<>0then|iferr_flag<>0then|end if'
$ echo $_RINDEX
54

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