Shell Programming and Scripting

Try this:

Code:

awk -F" - " '{gsub("[(\.]","")}{print $2}'

You can place "weird" characters within the brackets [], special characters must be escaped with a backslash.

Hi Franklin,

the expected output should be the whole field as what it is.

eg. FGI-LOM3100R \ LOM FGI REPORT (.

with your codes, the result is something like
FGI-LOM3100R LOM FGI REPORT
which is inaccurate.

again how can we extract the 3rd field totally without being affected by the chars within the field as delimiters?

i've tried using awk " - " but its giving me inaccurate answers if the field has a " - " within.

eg,


data: ID 123 - testing
output using awk comamnd: testing
desired output: testing



data: ID 456 - abc-abc.(
output using awk comamnd: abc-abc.(
desired output: abc


data: ID 7111 - abc - def
output using awk comamnd: def
desired output: abc - def

I've misread the question, try this:

Code:

awk -F" - " '{print $2}' file

Regards

Code:

awk '{$1="";$2="";$3=""; print }' input_file.txt | sed 's/^[ ]*//g'

Hi Guys,

Thanks for the replies so far. Haven't really quite hit the nail on the head yet though


data: ID 7111 - abc - def
output using awk -F" - " '{print $2}' file comamnd: abc
desired output: abc - def

its simple...

Code:

cat inputfile | cut -d"-" -f2-

fantastic. Thanks!