Shell Programming and Scripting

Hi Guys,

I have folder where the logs are generated (which is quite a few). I want to keep the recent n logs and delete the rest of them..

I am able to sort them by using ls -t.. but how to take it forward..

Can you people help me..

Thanks for the help in advance,

Regards,
Magesh..

one clunky way:

Code:

#!/bin/ksh
set -A arr  $(ls -t /directory/logfile*)
value=${#arr[*]} 

while [[ value -gt 6 ]] 
do
     x=$(( $value -1 ))  # arrays are zero-indexed
     rm -f ${arr[x]}      # remove the oldest 
     unset arr[x]          # remove the filename from the array
     value=${#arr[*]}   # get new array length
done

try something with arrays like this.

thanks man..i have already created one.. mine goes like this..

#/bin/sh
cd /clocal/dctrdata/user/dctrdat1/sysout
ls -rt > a.out
wc -l a.out|read lines dummy
delcnt=0
if [[ $lines -gt 5 ]]; then
delcnt=$(( lines - 5 ))
if [[ $delcnt -gt 0 ]] ; then
while read rec
do
# chnge the echo to rm -f $rec
echo $rec
delcnt=$(( delcnt -1 ))
[[ $delcnt -eq 0 ]] && break
done < a.out
fi
fi

You could try this command (assuming the names of your logs don't contain newline characters)

Code:

      LOGS_TO_KEEP=5
      ls -t1 | tail -n +$((LOGS_TO_KEEP+1)) | xargs -d '\n' rm -f