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Shell Programming and Scripting

To remove files with 0 File Size

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# 1  
Old 06-14-2009
To remove files with 0 File Size
Dear All,

I want to remove files having size of (0) that are generated once script is completed.

Here is the code

but i m not sure about /usr/bin

do i need to write /usr/bin, or the path of my script

/tmp/test

please find below the script logic

Code:
 
#!/usr/bin/ksh
for i in `ls -a`
do
  FILESIZE=`ls -l $i|awk '{print $5}'`
  if [ $FILESIZE -eq 0 ]
  then
    /usr/bin/rm $i
  fi
done

as /usr/bin contains all executable files.
# 2  
Old 06-14-2009
use find command its easy
Code:
find . -size 0 -exec rm {} \;

or if you want to use loop
use test command inside your for loop gothrough the man page of test
test ! -s filename
Last edited by vidyadhar85; 06-14-2009 at 03:44 PM..
# 3  
Old 06-14-2009
Thnkz vidyadhar85

I recieve followng output

Code:
find: 0652-018 An expression term lacks a required parameter

Can u please write the complete line for this case.
# 4  
Old 06-14-2009
one extra sapce was introuduced between -exec rm {} \ ;
try like this
Code:
 find . -size 0 -exec rm {} \;

# 5  
Old 06-14-2009
Quote:
Originally Posted by vidyadhar85
use find command its easy
Code:
find . -size 0 -exec rm {} \ ;


There should be no space between the backslash and the semi-colon.

More efficiently:

Code:
find . -size 0 -exec rm {} +

# 6  
Old 06-14-2009
with this you cam enter a size of your desire.
here all below 478 bytes get deleted:

size=0
size=`ls -l "file.txt | awk -F" " '{ print $5 }'`
if [ $size -gt 478 ];
then ((d++));
fi
# 7  
Old 06-14-2009
Quote:
Originally Posted by lowmaster
with this you cam enter a size of your desire.
here all below 478 bytes get deleted:

When you post code, please wrap it in [code] tags.
Quote:
Code:
size=0
size=`ls -l "file.txt | awk -F" " '{ print $5 }'`
if [ $size -gt 478 ];
then ((d++));
fi


Do you really propose calling two external programs (ls and awk) for every file?

(And you're missing a double quote.)
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