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Generate the File Attributes in the system

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# 1  
Old 06-12-2009
Generate the File Attributes in the system
Hello Folks,

I want to generate the file attributes of the system and needs to write into the text file.

I am running the command "ls -Rl" to get the details of the files from the current directory.

I am getting the output.

Code:
./linux-2.6.29.4/arch:
total 10
drwxr-xr-x  9 1138 5000  328 May 18 16:52 alpha
drwxr-xr-x 68 1138 5000 2104 May 18 16:52 arm
drwxr-xr-x 11 1138 5000  352 May 18 16:52 avr32
drwxr-xr-x 17 1138 5000  552 May 18 16:52 blackfin
drwxr-xr-x  8 1138 5000  272 May 18 16:52 cris
drwxr-xr-x  7 1138 5000  288 May 18 16:52 frv
drwxr-xr-x  8 1138 5000  392 May 18 16:52 h8300
drwxr-xr-x 17 1138 5000  552 May 18 16:52 ia64
-rw-r--r--  1 1138 5000 3022 May 18 16:52 Kconfig
drwxr-xr-x  9 1138 5000  304 May 18 16:52 m32r
drwxr-xr-x 22 1138 5000  608 May 18 16:52 m68k
drwxr-xr-x  7 1138 5000  280 May 18 16:52 m68knommu
drwxr-xr-x 35 1138 5000  944 May 18 16:52 mips
drwxr-xr-x 11 1138 5000  368 May 18 16:52 mn10300
drwxr-xr-x 10 1138 5000  408 May 18 16:52 parisc
drwxr-xr-x 14 1138 5000  424 May 18 16:52 powerpc
drwxr-xr-x 13 1138 5000  424 May 18 16:52 s390
drwxr-xr-x 15 1138 5000  472 May 18 16:52 sh
drwxr-xr-x 11 1138 5000  344 May 18 16:52 sparc
drwxr-xr-x 11 1138 5000  752 May 18 16:52 um
drwxr-xr-x 23 1138 5000  728 May 18 16:52 x86
drwxr-xr-x 10 1138 5000  328 May 18 16:52 xtensa

./linux-2.6.29.4/arch/alpha:
total 52
drwxr-xr-x 3 1138 5000   248 May 18 16:52 boot
-rw-r--r-- 1 1138 5000 20414 May 18 16:52 defconfig
drwxr-xr-x 3 1138 5000    72 May 18 16:52 include
-rw-r--r-- 1 1138 5000 19491 May 18 16:52 Kconfig
-rw-r--r-- 1 1138 5000  1355 May 18 16:52 Kconfig.debug
drwxr-xr-x 2 1138 5000  2384 May 18 16:52 kernel
drwxr-xr-x 2 1138 5000  1688 May 18 16:52 lib
-rw-r--r-- 1 1138 5000  2258 May 18 16:52 Makefile
drwxr-xr-x 2 1138 5000   152 May 18 16:52 math-emu
drwxr-xr-x 2 1138 5000   176 May 18 16:52 mm
drwxr-xr-x 2 1138 5000   256 May 18 16:52 oprofile

I want the output through the script that converts the output in the below mentioned format

I want the output in such a way, each file shows the full path from the "/" directory.

Code:
total 10
drwxr-xr-x  9 1138 5000  328 May 18 16:52 /usr/src/kernels/linux-2.6.29.4/archalpha
drwxr-xr-x 68 1138 5000 2104 May 18 16:52 /usr/src/kernels/linux-2.6.29.4/archarm
drwxr-xr-x 11 1138 5000  352 May 18 16:52 /usr/src/kernels/linux-2.6.29.4/archavr32

I have tried many sed regex but I did not make it work.

Could you please help me out to write this script?

Thanks,
Saurabh
# 2  
Old 06-12-2009
find command will give almost similar kind of o/p except two extra fields in the begining
you can get rid of that using awk or something else
Code:
find . -ls -long

# 3  
Old 06-12-2009
Thanks for the help. The solution was really meant to me.

However, I have only one issue. In this list, I want the details of the device file that contains the major num and minor number. If I could get this details, it would be great.

Is there any command with this command to get that details?

Thanks,
Saurabh
# 4  
Old 06-12-2009
read the find man page
Quote:
-ls
Always evaluates to the value True. Causes the current path name to be printed together with its associated statistics. These statistics include
the following:
* I-node number
* Size in kilobytes (1024 bytes)
* Protection mode
* Number of hard links
* User
* Group
* Size in bytes
* Modification time
If the file is a special file, the size field contains the major and minor device numbers. If the file is a symbolic link, the path name of the
linked-to file is printed preceded by the -> (hyphen, greater than) symbols. Formatting is similar to that of the ls -filds command, however
formatting is done internally without executing the ls command, therefore differences in output with the ls command may exist, such as with the
protection mode.
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