Shell Programming and Scripting

Hi

I have to validate the user ids. It should be numeric. I am using following code
echo $input | grep '^[0-9]\{11\} > /dev/null
if [ $? = 1 ]
echo "error"
else
echo "Success"
fi
But when i entered user id as 828^&% the output is
[2] 8565
[3] 8566
-bash: ^: command not found
Means when i entered specila characters i am getting the above output. Can anyone help me out.

Thanx

quote your $input variable.

alternatively, if you have Python,

Code:

#!/usr/bin/env python
import sys
userinput = sys.argv[1]
if userinput.isdigit() and len(userinput)==11:
    print "ok"
else:
    print "not ok"

output:

Code:

# ./test.py 12323332
not ok
# ./test.py 12345678901
ok
# ./test.py "sdfs$%%^%&"
not ok

Code:

 
echo "0920920-902992" | awk '$0 ~/[^0-9-]/ {print "non numeric" }'

here i have a concern forgot to mention that user allowed to entered user id range like

0920920-902992 (valid)
92920-9292%^& ( invalid)

so i need to do special character validation which allows '-' and numerics only.

i changed the validation above a bit i think it is OK.