Shell Programming and Scripting

This is the file structure:

Code:

DESKTOP/Root of Photo Folders/Folder1qweqwasdfsd/*jpg
DESKTOP/Root of Photo Folders/Folder2asdasdasd/*jpg
DESKTOP/Root of Photo Folders/Folder3asdadfhgasdf/*jpg
DESKTOP/Root of Photo Folders/Folder4qwetwdfsdfg/*jpg
DESKTOP/Root of Photo Folders/Folder54236fdsghsdgf/*jpg

I would like to copy all jpg's out of these folders into a single folder.

How might I do this simply and with a single command or two?

Code:

find ./ -name *.jpg -exec mv '{}' /path/to/destination \;

I would recommend echoing '{} \; before actually moving them

Thanks, didn't quite work because there were some duplicate names and .JPG is a different extension from .jpg (and it was a 50/50 mixed bag, even within the same directories *sigh*)

But thanks for the suggestion!

Then use a regular expression, or upcase or dncase all the files prior to the find command that was listed....

You can eliminate dups with a find ... | tr ... | sort | uniq > filename.ext
Then cat filename.ext | xorgs ...
or
edit filename.ext to convert it to a script
or
the possibilities are abundant

Are you trying to de-dup, or just move files, or both, or something else?

cp DESKTOP/Root of Photo Folders/Folder*/*jpg your_new_folder

OR
Execute this small script:

for file in DESKTOP/Root of Photo Folders/Folder*/*jpg;do
cp $file your_newfolder
done