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sed pattern range

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# 8  
Old 06-18-2009
The following sed command replaces all hashes between the first occurrence of left the brace and the first occurrence of right brace.
Code:
sed ':a ; s/^\([^(]*([^)#]*\)#\([^)]*).*\)/\1 \2/; ta'

# 9  
Old 06-18-2009
Thanks for the effort, can't seem to get it to work though. gives me an error.

Code:
N="text1#text2#text3(var1#var2#var3)#text4(var4#var5#var6)"
N=`echo $N | sed ':a ; s/^\([^(]*([^)#]*\)#\([^)]*).*\)/\1 \2/; ta'`
echo $N

gives me:

sed: The label :a ; s/^\([^(]*([^)#]*\)#\([^)]*).*\)/\1 \2/; ta is greater than eight characters.
# 10  
Old 06-18-2009
Try write one command on one line:
Code:
sed -e '
:a
s/^\([^(]*([^)#]*\)#\([^)]*).*\)/\1 \2/
ta
'

If your shell doesn't support multiline quotes, you can try escaping each newline with a backslash.
# 11  
Old 06-19-2009
No error now but only doing the first occurance.

Code:
N="text1#text2#text3(var1#var2#var3)#text4(var4#var5#var6)"
N=`echo $N |
sed -e '
:a
s/^\([^(]*([^)#]*\)#\([^)]*).*\)/\1 \2/
ta
'`

echo $N

output: text1#text2#text3(var1 var2 var3)#text4(var4#var5#var6)
# 12  
Old 06-19-2009
I thought, that's what you want. Please specify once again the input and the output you should want to receive.
# 13  
Old 06-19-2009
oh looking back that's my mistake.

need,

output: text1#text2#text3(var1 var2 var3)#text4(var4 var5 var6)
# 14  
Old 06-19-2009
The following should do.

Code:
sed '
:a
s/\([^(]*([^)#]*\)#\([^)]*).*\)/\1 \2/g
ta
' input_file
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