Shell Programming and Scripting

Hi

I am trying to write a shell script which should take the file as standard input. As file(content and name both) will change for each run. It should read the file line by line. with each line I have to perform certain operation.
For example
I have i file foo, it looks like
/usr/doc/abc
/usr/xyz/xyz

I have to print name of file in each path expected output is
abc
xyz

Pl suggest me with full code
Regards
Shashi

Since it's your first post here, you're asking for "full code" without showing what you tried so far, for a problem that's very basic and has been answered in a lot of threads, I'm going out on a limb here and ask: Homework?

==========================================
> cat > a.sh
#!/bin/bash

exec 6<&0
exec < a.sh
while read line
do
echo $line
done
exec 0<&6
'ctrl-D'
>
>
> ./a.sh
#!/bin/bash

exec 6<&0
exec < a.sh
while read line
do
echo $line
done
exec 0<&6
==========================================

You could actually search with "redirect stdin" on google.

Thanks for your reply

I had following code

#!/bin/bash

processLine(){
line="$@" # get all args
echo $line
}
FILE =""
FILE="$1"
# make sure file exist and readable
if [ ! -f $FILE ]; then
echo "$FILE : does not exists"
exit 1
elif [ ! -r $FILE ]; then
echo "$FILE: can not read"
exit 2
fi

exec 0<$FILE
while read line
do
# use $line variable to process line in processLine() function
processLine $line
done
exit 0


Through this code I am able to read line by line but now my requirement is
it should print some lines(say 10) then it should wait for hitting return key then print another 10 line. Just like the way we see help in linux some lines printed then it waits for hitting some key

pl suggest

Regards
Shashi

a little hint:

set a counter while printing, when it reaches 10, read a carriage return from stdin (in my code, it would be '&6' and then proceed.