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incremental addition of hex decimal number in one field

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# 1  
Old 06-01-2009
incremental addition of hex decimal number in one field
Hi I want to incremental add hex decimal number to a particula field in file

eg: addr =123 dept1=0
addr = 345 dept2 =1
addr2 = 124 dept3 =2
.
.
.
.
.
.
addr3 =567 dept15 =f

Is there any command which add incremental number to particula field in file

thank you
# 2  
Old 06-01-2009
Can you explain your requirement more clearly?

you can convert base with unix bc.. and make a loop to increment.

eg

Code:
for i in 100 101 102 103; do  echo "ibase=10;obase=16;$i" | bc; done


hope it helps.
# 3  
Old 06-01-2009
my requirement is simple i want to deptno field to get incremental hex value..i am doing manually by entering 0 1 2 3 for each field in the file..i want it one shot...
# 4  
Old 06-01-2009
Quote:
Originally Posted by diddi_linux
my requirement is simple i want to deptno field to get incremental hex value..i am doing manually by entering 0 1 2 3 for each field in the file..i want it one shot...
Here's one way to do it:

Code:
$
$ perl -e 'foreach $i (0..30){printf "dept%d = %x\n",$i,$i}'
dept0 = 0
dept1 = 1
dept2 = 2
dept3 = 3
dept4 = 4
dept5 = 5
dept6 = 6
dept7 = 7
dept8 = 8
dept9 = 9
dept10 = a
dept11 = b
dept12 = c
dept13 = d
dept14 = e
dept15 = f
dept16 = 10
dept17 = 11
dept18 = 12
dept19 = 13
dept20 = 14
dept21 = 15
dept22 = 16
dept23 = 17
dept24 = 18
dept25 = 19
dept26 = 1a
dept27 = 1b
dept28 = 1c
dept29 = 1d
dept30 = 1e
$

tyler_durden
# 5  
Old 06-01-2009
similarly with awk
Code:
 awk '{printf "%s%d %x\n", $1, ++j,i++}' file

# 6  
Old 06-03-2009
thank you all..i would like get values addr field from one and dept field incremental value of hexdecimal
addr={1st field from any other file1} dept={incremental value of hex decimal }
addr= 601 dept =0
addr =602 dept=1
addr = 603 dept =2
.
.
.
.
addr =670 dept=1f
# 7  
Old 06-03-2009
Quote:
Originally Posted by diddi_linux
...i would like get values addr field from one and dept field incremental value of hexdecimal
addr={1st field from any other file1} dept={incremental value of hex decimal }
...
Assuming that you've captured and stored the first addr value from the file in $first:

Code:
$
$
$ perl -e '$first=601; foreach $i (0..69){printf "addr = %d dept = %x\n",($i+$first),$i}'
addr = 601 dept = 0
addr = 602 dept = 1
addr = 603 dept = 2
addr = 604 dept = 3
addr = 605 dept = 4
addr = 606 dept = 5
addr = 607 dept = 6
addr = 608 dept = 7
addr = 609 dept = 8
addr = 610 dept = 9
addr = 611 dept = a
addr = 612 dept = b
...
... <skipped a few lines>
...
addr = 668 dept = 43
addr = 669 dept = 44
addr = 670 dept = 45
$
$

tyler_durden
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