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# 1  
Old 05-29-2009
sed issues
Hi guys, not that used to using sed beyond the simple substitution. I am trying to check for a program (program1) and if it exists replace the standard output "program1" with a "program1(part1 part2) output if said program exists.

Code:
SW="program1 program2"
PROGRAM_TEST='echo "$SW" | grep "program1"'
if test ! "$PROGRAM_TEST" = "" ;then
     PROGRAM1_LIST="part1 part2"
     sed -e 's/program1/program1($PROGRAM1_LIST)/g' $SW > $SW2
fi
if test "$SW2" = ""; then
     echo "software: $SW"
     else
     echo "software: $SW2"
fi

I believe the problem is to do with the sed substitution as the error given is:

Code:
sed: Cannot find or open file program1
sed: Cannot find or open file program2

Any help or ideas on getting this to work?
# 2  
Old 05-29-2009
Code:
$
$ echo "program1 program2" | grep "program1" 1>/dev/null && echo "program1(part1 part2)"
program1(part1 part2)
$
$ echo "program3 program2" | grep "program1" 1>/dev/null && echo "program1(part1 part2)"
$
$

tyler_durden
# 3  
Old 06-02-2009
Thanks. worked it into a fix Smilie
# 4  
Old 06-02-2009
Quote:
Originally Posted by mikepegg
Hi guys, not that used to using sed beyond the simple substitution. I am trying to check for a program (program1) and if it exists replace the standard output "program1" with a "program1(part1 part2) output if said program exists.

Code:
SW="program1 program2"
PROGRAM_TEST='echo "$SW" | grep "program1"'
if test ! "$PROGRAM_TEST" = "" ;then
     PROGRAM1_LIST="part1 part2"
     sed -e 's/program1/program1($PROGRAM1_LIST)/g' $SW > $SW2
fi
if test "$SW2" = ""; then
     echo "software: $SW"
     else
     echo "software: $SW2"
fi

I believe the problem is to do with the sed substitution as the error given is:

Code:
sed: Cannot find or open file program1
sed: Cannot find or open file program2

Any help or ideas on getting this to work?

You haven't checked whether program1 or program2 exists. All you have done is check whether they are part of the string $SW (for which you don't need grep).
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