Shell Programming and Scripting

Hi Frdz,

i am using rsync to transfer files from source to destination. but i have one criteria like i have to tranfer only links from source to destination.

in home/test/po folder i have

kiran/test1 -> /home/test/lo/fg
kiran/test2 -> /home/test/lo/fg2

like links are available.
and i am running the following command.

rsync -rvcpogtl -e "ssh -p1223" --exclude='?' /home/test/toDay/ username@hostname:/home > test.log


what to place in the value of exclude option??

Instead of --exclude, you can do --files-from=- to get from stdin the list of files to rsync. So you can do:

Code:

find /home/test/po -type l -print | rsync -rvcpogtl -e "ssh -p1223" --files-from=- /home/test/po username@hostname:/home >test.log

Be careful though and do a dry-run and a limited wet-run first. You have three different directories: the one find uses, the one rsync starts from, and the destination of rsync. Find outputs absolute path names, and combined with the -r option, this can have unexpected results. You might need to run find's output through sed to remove the starting path name, for instance.