Shell Programming and Scripting

Hi,

Please guide to pass an array as a arg to a script...


for example,

I have a script small.sh to find the small no of given arg as below...

#! /bin/sh

# this script is for finding the small number

set -A arr_no_updates

small=$1
i=1
for arr in $@
do
if [ $arr -ne 0 ]
then
if [ $arr -le small ]
then
small=$arr
fi
fi

i=$(($i+1))
done
echo $small


Now i like to use this script for muliple times in another script called secondscript.sh


please help me on the following
1.how to call the small.sh
2.how to pass the array as arg
3.how to get the result


I tried for the non array codes, i could get the perfect result with the below lines..

chmod 777 small.sh
./small.sh 10 20 30

please help me hw to arg a array.. Thankyou all in advance...

I still don't understand why you wanna store arg into array internally ita stored in array only by using for loop you can access it one by one
and inside for loop why are you incrementing i??

Hi vidyadhar85,

Sorry if my question confuse you..
actually i want to pass an array as argument..
please find the script named small.sh.. This script is to find small no from a list..

i want to call this small.sh in another script secondscript.sh, where as i wish to pass a array as argument..

for ex, if i have 3 arrays in secondscript.sh. i want to use small.sh to find the smallest no of each array..

hope the scenario is clear now.

Code:

result="$(small.sh ${arrayname[*]})"
result="$(small.sh ${arrayname[@]})"